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Computer Science Engineering (CSE) Exam  >  Computer Science Engineering (CSE) Questions  >  The essential content(s) in each entry of a p... Start Learning for Free
The essential content(s) in each entry of a page table is / are
  • a)
    Virtual page number
  • b)
    Page frame number
  • c)
    Both virtual page number and page frame number
  • d)
    Access right information
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
The essential content(s) in each entry of a page table is / area)Virtu...
A page table entry must contain Page frame number. Virtual page number is typically used as index in page table to get the corresponding page frame number. See this for details.
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Most Upvoted Answer
The essential content(s) in each entry of a page table is / area)Virtu...
Understanding Page Tables
In operating systems, a page table is a crucial data structure used in virtual memory management. It helps the system translate virtual addresses to physical addresses.
Essential Components of a Page Table Entry
- Virtual Page Number (VPN):
This is the index that identifies a specific page in virtual memory. Each process has its own virtual address space, and the VPN helps the system keep track of which virtual page corresponds to which physical page.
- Page Frame Number (PFN):
This indicates the actual location in physical memory (RAM) where the corresponding virtual page is stored. The PFN is key for mapping virtual addresses to physical addresses, allowing the CPU to access the data efficiently.
Correct Answer Explanation
The correct answer is option 'B' because:
- The essential content of each entry in a page table primarily consists of the Page Frame Number (PFN).
- The PFN is used to locate the physical memory frame where the actual data resides, enabling effective memory management.
Access Rights Information
While access rights and other flags (like dirty bit, reference bit) can be part of a page table entry, they are not considered essential for the basic function of mapping virtual to physical memory. Therefore, they are not included in the essential content that defines the primary purpose of a page table.
In summary, the main focus of a page table is to maintain the mapping between virtual page numbers and their corresponding page frame numbers in physical memory, justifying why option 'B' is the correct answer.
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A processor uses 2-level page tables for virtual to physical address translation. Page tables for both levels are stored in the main memory. Virtual and physical addresses are both 32 bits wide. The memory is byte addressable. For virtual to physical address translation, the 10 most significant bits of the virtual address are used as index into the first level page table while the next 10 bits are used as index into the second level page table. The 12 least significant bits of the virtual address are used as offset within the page. Assume that the page table entries in both levels of page tables are 4 bytes wide. Further, the processor has a translation look-aside buffer (TLB), with a hit rate of 96%. The TLB caches recently used virtual page numbers and the corresponding physical page numbers. The processor also has a physically addressed cache with a hit rate of 90%. Main memory access time is 10 ns, cache access time is 1 ns, and TLB access time is also 1 ns. Assuming that no page faults occur, the average time taken to access a virtual address is approximately (to the nearest 0.5 ns)

A processor uses 2-level page tables for virtual to physical address translation. Page tables for both levels are stored in the main memory. Virtual and physical addresses are both 32 bits wide. The memory is byte addressable. For virtual to physical address translation, the 10 most significant bits of the virtual address are used as index into the first level page table while the next 10 bits are used as index into the second level page table. The 12 least significant bits of the virtual address are used as offset within the page. Assume that the page table entries in both levels of page tables are 4 bytes wide. Further, the processor has a translation look-aside buffer (TLB), with a hit rate of 96%. The TLB caches recently used virtual page numbers and the corresponding physical page numbers. The processor also has a physically addressed cache with a hit rate of 90%. Main memory access time is 10 ns, cache access time is 1 ns, and TLB access time is also 1 ns. Suppose a process has only the following pages in its virtual address space: two contiguous code pages starting at virtual address 0x00000000, two contiguous data pages starting at virtual address 000400000, and a stack page starting at virtual address 0FFFFF000. The amount of memory required for storing the page tables of this process is

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The essential content(s) in each entry of a page table is / area)Virtual page numberb)Page frame numberc)Both virtual page number and page frame numberd)Access right informationCorrect answer is option 'B'. Can you explain this answer?
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