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For a dilute solution containing 2.5 g of a non-volatile nonelectrolytesolute in 100 g of water, the elevationin boiling point at 1 atm pressure is 2°C. Assumingconcentration of solute is much lower than the concentrationof solvent, the vapour pressure (mm of Hg) of the solutionis (take Kb = 0.76 K kg mol–1) (2012)
  • a)
    724
  • b)
    740
  • c)
    736
  • d)
    718
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
For a dilute solution containing 2.5 g of a non-volatile nonelectrolyt...
From Raoult law relation,
When the concentration of solute is much lower than the concentration of solvent,
           .... (i)
From elevation in boiling point, ΔTb = Kb × m
2 = 0.76 × m
m = 2/0.76              ...(ii)
From (i) and (ii), p = 724 mm
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For a dilute solution containing 2.5 g of a non-volatile nonelectrolytesolute in 100 g of water, the elevationin boiling point at 1 atm pressure is 2°C. Assumingconcentration of solute is much lower than the concentrationof solvent, the vapour pressure (mm of Hg) of the solutionis (take Kb = 0.76 K kg mol–1) (2012)a)724b)740c)736d)718Correct answer is option 'A'. Can you explain this answer?
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For a dilute solution containing 2.5 g of a non-volatile nonelectrolytesolute in 100 g of water, the elevationin boiling point at 1 atm pressure is 2°C. Assumingconcentration of solute is much lower than the concentrationof solvent, the vapour pressure (mm of Hg) of the solutionis (take Kb = 0.76 K kg mol–1) (2012)a)724b)740c)736d)718Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about For a dilute solution containing 2.5 g of a non-volatile nonelectrolytesolute in 100 g of water, the elevationin boiling point at 1 atm pressure is 2°C. Assumingconcentration of solute is much lower than the concentrationof solvent, the vapour pressure (mm of Hg) of the solutionis (take Kb = 0.76 K kg mol–1) (2012)a)724b)740c)736d)718Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a dilute solution containing 2.5 g of a non-volatile nonelectrolytesolute in 100 g of water, the elevationin boiling point at 1 atm pressure is 2°C. Assumingconcentration of solute is much lower than the concentrationof solvent, the vapour pressure (mm of Hg) of the solutionis (take Kb = 0.76 K kg mol–1) (2012)a)724b)740c)736d)718Correct answer is option 'A'. Can you explain this answer?.
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