Question Description
For a dilute solution containing 2.5 g of a non-volatile, non-electrolyte solute in 100 g of water, the elevation in boiling point at 1 atm is 2C. Assuming concentration of the solute is much lower than that of solvent, vapour pressure (mm of Hg) of the solution is (Kb =0.76 K kg mol-1a)724b)740c)736d)718Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about For a dilute solution containing 2.5 g of a non-volatile, non-electrolyte solute in 100 g of water, the elevation in boiling point at 1 atm is 2C. Assuming concentration of the solute is much lower than that of solvent, vapour pressure (mm of Hg) of the solution is (Kb =0.76 K kg mol-1a)724b)740c)736d)718Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a dilute solution containing 2.5 g of a non-volatile, non-electrolyte solute in 100 g of water, the elevation in boiling point at 1 atm is 2C. Assuming concentration of the solute is much lower than that of solvent, vapour pressure (mm of Hg) of the solution is (Kb =0.76 K kg mol-1a)724b)740c)736d)718Correct answer is option 'A'. Can you explain this answer?.

Solutions for For a dilute solution containing 2.5 g of a non-volatile, non-electrolyte solute in 100 g of water, the elevation in boiling point at 1 atm is 2C. Assuming concentration of the solute is much lower than that of solvent, vapour pressure (mm of Hg) of the solution is (Kb =0.76 K kg mol-1a)724b)740c)736d)718Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of For a dilute solution containing 2.5 g of a non-volatile, non-electrolyte solute in 100 g of water, the elevation in boiling point at 1 atm is 2C. Assuming concentration of the solute is much lower than that of solvent, vapour pressure (mm of Hg) of the solution is (Kb =0.76 K kg mol-1a)724b)740c)736d)718Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of For a dilute solution containing 2.5 g of a non-volatile, non-electrolyte solute in 100 g of water, the elevation in boiling point at 1 atm is 2C. Assuming concentration of the solute is much lower than that of solvent, vapour pressure (mm of Hg) of the solution is (Kb =0.76 K kg mol-1a)724b)740c)736d)718Correct answer is option 'A'. Can you explain this answer?, a detailed solution for For a dilute solution containing 2.5 g of a non-volatile, non-electrolyte solute in 100 g of water, the elevation in boiling point at 1 atm is 2C. Assuming concentration of the solute is much lower than that of solvent, vapour pressure (mm of Hg) of the solution is (Kb =0.76 K kg mol-1a)724b)740c)736d)718Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of For a dilute solution containing 2.5 g of a non-volatile, non-electrolyte solute in 100 g of water, the elevation in boiling point at 1 atm is 2C. Assuming concentration of the solute is much lower than that of solvent, vapour pressure (mm of Hg) of the solution is (Kb =0.76 K kg mol-1a)724b)740c)736d)718Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice For a dilute solution containing 2.5 g of a non-volatile, non-electrolyte solute in 100 g of water, the elevation in boiling point at 1 atm is 2C. Assuming concentration of the solute is much lower than that of solvent, vapour pressure (mm of Hg) of the solution is (Kb =0.76 K kg mol-1a)724b)740c)736d)718Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.