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A population is in Hardy –Weinberg equilibrium for a gene with only two alleles (P and p). If the frequency of the allele P is 0.8, the frequency of the heterozygote in the population is ____ (Round off to two decimal places)
    Correct answer is '0.32'. Can you explain this answer?
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    A population is in Hardy –Weinberg equilibrium for a gene with o...
    Allele frequency of P is 0.8, then allele frequency for p =0.2. so the frequency of heterozygotes = 2 X PX p = 2 x 0.8 X 0.2 = 0.32.
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    A population is in Hardy –Weinberg equilibrium for a gene with only two alleles (P and p). If the frequency of the allele P is 0.8, the frequency of the heterozygote in the population is ____ (Round off to two decimal places)Correct answer is '0.32'. Can you explain this answer?
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    A population is in Hardy –Weinberg equilibrium for a gene with only two alleles (P and p). If the frequency of the allele P is 0.8, the frequency of the heterozygote in the population is ____ (Round off to two decimal places)Correct answer is '0.32'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about A population is in Hardy –Weinberg equilibrium for a gene with only two alleles (P and p). If the frequency of the allele P is 0.8, the frequency of the heterozygote in the population is ____ (Round off to two decimal places)Correct answer is '0.32'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A population is in Hardy –Weinberg equilibrium for a gene with only two alleles (P and p). If the frequency of the allele P is 0.8, the frequency of the heterozygote in the population is ____ (Round off to two decimal places)Correct answer is '0.32'. Can you explain this answer?.
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