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In a population at Hardy- Weinberg equilibrium, the frequency of a recessive allele that causes a genetic disorder is 0.3. What percentage of the population is expected to suffer from this condition?
  • a)
    9%
  • b)
    0.3%
  • c)
    0.09%
  • d)
    30%
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
In a population at Hardy- Weinberg equilibrium, the frequency of a rec...
We are given q is equals to 0.3
genotypic frequency q square is equals to 0.09
calculate it in percentage 0.09 x 100 is equals to 9%
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In a population at Hardy- Weinberg equilibrium, the frequency of a recessive allele that causes a genetic disorder is 0.3. What percentage of the population is expected to suffer from this condition?a)9%b)0.3%c)0.09%d)30%Correct answer is option 'A'. Can you explain this answer?
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In a population at Hardy- Weinberg equilibrium, the frequency of a recessive allele that causes a genetic disorder is 0.3. What percentage of the population is expected to suffer from this condition?a)9%b)0.3%c)0.09%d)30%Correct answer is option 'A'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about In a population at Hardy- Weinberg equilibrium, the frequency of a recessive allele that causes a genetic disorder is 0.3. What percentage of the population is expected to suffer from this condition?a)9%b)0.3%c)0.09%d)30%Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a population at Hardy- Weinberg equilibrium, the frequency of a recessive allele that causes a genetic disorder is 0.3. What percentage of the population is expected to suffer from this condition?a)9%b)0.3%c)0.09%d)30%Correct answer is option 'A'. Can you explain this answer?.
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