The geometry of H2S and its dipole moment are (1999 - 2 Marks)a)angula...
To determine the geometry of H2S, we need to look at the electron pair arrangement and the molecular shape.
1. Electron Pair Arrangement:
In H2S, there are two regions of electron density around the central sulfur atom. These regions can be occupied by either bonding pairs or lone pairs of electrons.
2. Valence Shell Electron Pair Repulsion (VSEPR) Theory:
The VSEPR theory states that electron pairs around a central atom will arrange themselves in a way that minimizes repulsion between them.
3. Molecular Shape:
Based on the VSEPR theory, the electron pair arrangement in H2S is determined to be bent/angular. This is because the two bonding pairs of electrons and the two lone pairs of electrons around the central sulfur atom repel each other, causing the molecule to adopt a bent shape.
4. Dipole Moment:
The dipole moment is a measure of the polarity of a molecule. It is determined by the difference in electronegativity between the atoms involved and the molecular geometry.
In the case of H2S, the sulfur atom is more electronegative than the hydrogen atoms. This means that the sulfur atom attracts the bonding electrons more strongly, resulting in a polar covalent bond.
The bent/angular geometry of H2S means that the dipole moments of the two S-H bonds do not cancel each other out. The dipole moment vectors do not have equal magnitude and are not directly opposite to each other. As a result, the molecule has a net dipole moment, making it polar.
Therefore, the correct answer is option 'A' - angular and non-zero.
The geometry of H2S and its dipole moment are (1999 - 2 Marks)a)angula...
H2O and H2S have same structure
So, geometry angular or bent
since, electronegativity of S is more than H so , polarization will be towards sulphur and due to bent shape net dipole moment becomes upwards.