IIT JAM Exam  >  IIT JAM Questions  >  A relaxed bacterial circular chromosome has h... Start Learning for Free
A relaxed bacterial circular chromosome has helix turn 70.  The DNA is supercoiled by -10.  The original linking number of the circular DNA would be _________
    Correct answer is '70'. Can you explain this answer?
    Verified Answer
    A relaxed bacterial circular chromosome has helix turn 70. The DNA is ...
     The Linking number (Lk) is the number of times the axis of a DNA molecule crosses itself around the central axis. Lk determine the degree of supercoiling. The linking number of a closed DNA molecule,
    Lk = twist + writhe.
    For relaxed chromosome, writhe = 0, hence original Lk of the DNA = twist = 70.
    View all questions of this test
    Most Upvoted Answer
    A relaxed bacterial circular chromosome has helix turn 70. The DNA is ...
    Explanation:

    1. Relaxed Bacterial Circular Chromosome:
    In a relaxed bacterial circular chromosome, the DNA is not under any torsional stress or strain. The DNA molecule is in a relaxed state and is not subjected to any twisting or supercoiling.

    2. Helix Turn:
    The helix turn is a measure of the number of complete turns made by the DNA helix along the length of the DNA molecule. It is a measure of the helical structure of DNA.

    3. Supercoiling:
    Supercoiling refers to the twisting or coiling of a DNA molecule upon itself. It can be either positive or negative. In positive supercoiling, the DNA is overwound, while in negative supercoiling, the DNA is underwound.

    4. Linking Number:
    The linking number (Lk) is a topological property of a closed DNA molecule, such as a circular chromosome. It represents the number of times one strand of DNA crosses over or under the other strand in a closed DNA molecule.

    5. Relationship between Linking Number, Helix Turn, and Supercoiling:
    The linking number of a circular DNA molecule can be calculated using the formula:

    Lk = Tw + Wr

    Where Lk is the linking number, Tw is the number of helix turns, and Wr is the number of supercoils.

    In the given scenario, the helix turn is 70 and the supercoiling is -10. Since the DNA is supercoiled by -10, Wr is -10.

    Thus, the linking number can be calculated as:

    Lk = 70 + (-10) = 60

    6. The Original Linking Number:
    The original linking number refers to the linking number of the DNA molecule in its relaxed state, before any supercoiling or torsional stress is applied. In this case, the DNA is relaxed, so the original linking number is equal to the linking number calculated above, which is 60.

    However, it is important to note that the given answer is '70'. This may indicate an error in the question or answer options, as the original linking number should be equal to the calculated linking number (which is 60) in a relaxed state.
    Explore Courses for IIT JAM exam
    A relaxed bacterial circular chromosome has helix turn 70. The DNA is supercoiled by -10. The original linking number of the circular DNA would be _________Correct answer is '70'. Can you explain this answer?
    Question Description
    A relaxed bacterial circular chromosome has helix turn 70. The DNA is supercoiled by -10. The original linking number of the circular DNA would be _________Correct answer is '70'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about A relaxed bacterial circular chromosome has helix turn 70. The DNA is supercoiled by -10. The original linking number of the circular DNA would be _________Correct answer is '70'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A relaxed bacterial circular chromosome has helix turn 70. The DNA is supercoiled by -10. The original linking number of the circular DNA would be _________Correct answer is '70'. Can you explain this answer?.
    Solutions for A relaxed bacterial circular chromosome has helix turn 70. The DNA is supercoiled by -10. The original linking number of the circular DNA would be _________Correct answer is '70'. Can you explain this answer? in English & in Hindi are available as part of our courses for IIT JAM. Download more important topics, notes, lectures and mock test series for IIT JAM Exam by signing up for free.
    Here you can find the meaning of A relaxed bacterial circular chromosome has helix turn 70. The DNA is supercoiled by -10. The original linking number of the circular DNA would be _________Correct answer is '70'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A relaxed bacterial circular chromosome has helix turn 70. The DNA is supercoiled by -10. The original linking number of the circular DNA would be _________Correct answer is '70'. Can you explain this answer?, a detailed solution for A relaxed bacterial circular chromosome has helix turn 70. The DNA is supercoiled by -10. The original linking number of the circular DNA would be _________Correct answer is '70'. Can you explain this answer? has been provided alongside types of A relaxed bacterial circular chromosome has helix turn 70. The DNA is supercoiled by -10. The original linking number of the circular DNA would be _________Correct answer is '70'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A relaxed bacterial circular chromosome has helix turn 70. The DNA is supercoiled by -10. The original linking number of the circular DNA would be _________Correct answer is '70'. Can you explain this answer? tests, examples and also practice IIT JAM tests.
    Explore Courses for IIT JAM exam

    Suggested Free Tests

    Signup for Free!
    Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
    10M+ students study on EduRev