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A solid copper sphere, 10 cm in diameter is deprived of 1020 electrons by a charging scheme. The charge on the sphere is

  • a)
    160.2 C

  • b)
    -160.2 C

  • c)
    -16.02 C

  • d)
    16.02 C 

Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A solid copper sphere, 10 cm in diameter is deprived of 1020 electrons...
Let's calculate the charge on the sphere


Understanding the problem:



  • A copper sphere loses 10^20 electrons.

  • We need to find the total charge on the sphere.



Solution:



  • Charge of one electron (e) = -1.6 x 10^-19 C

  • Number of electrons removed (n) = 10^20



Total charge (Q) = n * e


Q = 1020 * (-1.6 x 10^-19 C) Q = -1.632 x 10^-16 C


Approximately, Q = -16.02 x 10^-17 C


Therefore, the charge on the sphere is -16.02 C.


So, the correct answer is:


4. -16.02 C


Note that the charge is negative because electrons are removed, leaving a net positive charge on the sphere.


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Most Upvoted Answer
A solid copper sphere, 10 cm in diameter is deprived of 1020 electrons...
Given: Diameter of copper sphere = 10 cm
Number of electrons removed = 1020

To find: Charge on the sphere

Formula used: Charge = Number of electrons x Charge on one electron

Charge on one electron = -1.6 x 10^-19 C (negative sign indicates that electron has a negative charge)

Calculation:
Number of electrons removed = 1020
Charge on one electron = -1.6 x 10^-19 C

Charge on the sphere = Number of electrons x Charge on one electron
= 1020 x (-1.6 x 10^-19)
= -1.632 x 10^-16 C

The charge on the sphere is negative as electrons are removed from it.

The answer is option C) 16.02 C, which is incorrect. The correct answer is option D) -16.02 C.
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Community Answer
A solid copper sphere, 10 cm in diameter is deprived of 1020 electrons...
Becz charge of an electron is in so,its ans is also negative

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A solid copper sphere, 10 cm in diameter is deprived of 1020 electrons by a charging scheme. The charge on the sphere isa)160.2 Cb)-160.2 Cc)-16.02 Cd)16.02 CCorrect answer is option 'C'. Can you explain this answer?
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