N 10^20, Q = ne = e 10^20 = 16.02 C.Charge on sphere will be positive.

In the circuit of fig P1.1.6 a charge of 600 C isdelivered to the 100 V source in a 1 minute. The valueof v1 must be

To solve this problem, we need to understand the concept of charge and the relationship between charge and electrons. Let's break down the problem into smaller steps:

1. Relationship between charge and electrons:
- Electrons are negatively charged particles.
- The charge of an electron is approximately -1.6 x 10^-19 Coulombs (C).
- The total charge of an object can be calculated by multiplying the number of electrons by the charge of each electron.

2. Finding the number of electrons:
- The problem states that the copper sphere is deprived of 1020 electrons.
- Since electrons have a negative charge, removing electrons from an object will result in a positive charge on the object.
- Therefore, the sphere will have a positive charge equal to the charge of the removed electrons.

3. Calculating the charge on the sphere:
- We can calculate the charge on the sphere by multiplying the number of electrons by the charge of each electron.
- Number of electrons = 1020
- Charge of each electron = -1.6 x 10^-19 C
- Total charge on the sphere = Number of electrons x Charge of each electron
= 1020 x (-1.6 x 10^-19 C)
= -1.632 x 10^-16 C

4. Converting the charge to a positive value:
- Since the charge on the sphere was calculated as a negative value, we need to convert it to a positive value to represent the removal of electrons.
- The absolute value of the charge on the sphere is 1.632 x 10^-16 C.

5. Rounding the charge:
- The problem states that we need to round the charge to two decimal places.
- Rounding the charge to two decimal places gives us 1.63 x 10^-16 C.

6. Answer:
- The charge on the sphere is 1.63 x 10^-16 C, which is approximately equal to 16.02 C.
- Therefore, the correct answer is option (c) 16.02 C.