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A cylindrical bar of L metres deforms by l cm. The strain in bar is
  • a)
    l/L
  • b)
    0.1 l/L
  • c)
    0.01 l/L
  • d)
    100 l/L
  • e)
    none of the above
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A cylindrical bar of L metres deforms by l cm. The strain in bar isa)l...
Strain is a measure of the deformation of an object relative to its original size. It is defined as the ratio of the change in length (deformation) to the original length of the object. In this case, we have a cylindrical bar that deforms by l cm, and we need to find the strain in the bar.

To calculate the strain in the bar, we can use the formula:

Strain = (Change in length) / (Original length)

Given that the bar deforms by l cm and the original length of the bar is L metres, we can substitute these values into the formula:

Strain = l cm / L metres

However, we need to ensure that the units are consistent. Since the original length is given in metres, we need to convert the deformation from centimeters to metres:

l cm = (l cm / 100) metres

Substituting this into the formula, we get:

Strain = (l cm / 100) metres / L metres

Simplifying the expression, we find:

Strain = l / (100 * L)

This is equivalent to:

Strain = 0.01 * (l / L)

Therefore, the strain in the bar is 0.01 times the ratio of the deformation to the original length.

Hence, the correct answer is option C: 0.01 l/L.
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Community Answer
A cylindrical bar of L metres deforms by l cm. The strain in bar isa)l...
Strain=change in length/original length
original length= L meter =100 L cm
change in length=l cm

so stain = l/100L =0.01l/L
hence option c is correct
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