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In a circle of radius 2 units, a diameter AB intersects a chord of length 2 units perpendicular at P. If AP > BP, then AP is equal toa)(2 + √5) unitsb)(2 + √3) unitsc)(2 + √2) unitsd)3 unitsCorrect answer is option 'B'. Can you explain this answer? for Defence 2024 is part of Defence preparation. The Question and answers have been prepared
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the Defence exam syllabus. Information about In a circle of radius 2 units, a diameter AB intersects a chord of length 2 units perpendicular at P. If AP > BP, then AP is equal toa)(2 + √5) unitsb)(2 + √3) unitsc)(2 + √2) unitsd)3 unitsCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Defence 2024 Exam.
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In a circle of radius 2 units, a diameter AB intersects a chord of length 2 units perpendicular at P. If AP > BP, then AP is equal toa)(2 + √5) unitsb)(2 + √3) unitsc)(2 + √2) unitsd)3 unitsCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for In a circle of radius 2 units, a diameter AB intersects a chord of length 2 units perpendicular at P. If AP > BP, then AP is equal toa)(2 + √5) unitsb)(2 + √3) unitsc)(2 + √2) unitsd)3 unitsCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of In a circle of radius 2 units, a diameter AB intersects a chord of length 2 units perpendicular at P. If AP > BP, then AP is equal toa)(2 + √5) unitsb)(2 + √3) unitsc)(2 + √2) unitsd)3 unitsCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice In a circle of radius 2 units, a diameter AB intersects a chord of length 2 units perpendicular at P. If AP > BP, then AP is equal toa)(2 + √5) unitsb)(2 + √3) unitsc)(2 + √2) unitsd)3 unitsCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Defence tests.