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Consider the Quicksort algorithm. Suppose there is a procedure for finding a pivot element which splits the list into two sub-lists each of which contains at least one-fifth of the elements. Let T(n) be the number of comparisons required to sort n elements. Then
  • a)
    T(n) <= 2T(n/5) + n
  • b)
    T(n) <= T(n/5) + T(4n/5) + n
  • c)
    T(n) <= 2T(4n/5) + n
  • d)
    T(n) <= 2T(n/2) + n
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Consider the Quicksort algorithm. Suppose there is a procedure for fin...
For the case where n/5 elements are in one subset, T(n/5) comparisons are needed for the first subset with n/5 elements, T(4n/5) is for the rest 4n/5 elements, and n is for finding the pivot. If there are more than n/5 elements in one set then other set will have less than 4n/5 elements and time complexity will be less than T(n/5) + T(4n/5) + n because recursion tree will be more balanced.
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Most Upvoted Answer
Consider the Quicksort algorithm. Suppose there is a procedure for fin...
Explanation:

The Quicksort algorithm is a divide-and-conquer sorting algorithm that works by selecting a pivot element from the array and partitioning the other elements into two sub-arrays, according to whether they are less than or greater than the pivot. The sub-arrays are then sorted recursively.

In this question, we are given that there is a procedure for finding a pivot element that splits the list into two sub-lists, each of which contains at least one-fifth of the elements.

Key Observation:
The key observation here is that after selecting a pivot element, the partitioning step divides the array into two sub-arrays, one of which contains at least one-fifth of the elements. This means that the size of the sub-array containing at least one-fifth of the elements is at most 4/5 times the size of the original array.

Explanation of the Options:
Let's go through each option and see which one is correct:

a) T(n) = 2T(n/5) + n
This option suggests that the number of comparisons required to sort n elements is twice the number of comparisons required to sort n/5 elements, plus n. This is not correct because we are given that the pivot splits the list into two sub-lists, each containing at least one-fifth of the elements. So, the size of the sub-array containing at least one-fifth of the elements is at most 4/5 times the size of the original array. Therefore, the recurrence relation should have a factor of 4/5 instead of 2.

b) T(n) = T(n/5) + T(4n/5) + n
This option suggests that the number of comparisons required to sort n elements is the number of comparisons required to sort n/5 elements, plus the number of comparisons required to sort 4n/5 elements, plus n. This is the correct recurrence relation because after selecting a pivot element, we divide the array into two sub-arrays, one of which contains at least one-fifth of the elements.

c) T(n) = 2T(4n/5) + n
This option suggests that the number of comparisons required to sort n elements is twice the number of comparisons required to sort 4n/5 elements, plus n. This is not correct because we are given that the pivot splits the list into two sub-lists, each containing at least one-fifth of the elements. So, the size of the sub-array containing at least one-fifth of the elements is at most 4/5 times the size of the original array. Therefore, the recurrence relation should have a factor of 4/5 instead of 2.

d) T(n) = 2T(n/2) + n
This option suggests that the number of comparisons required to sort n elements is twice the number of comparisons required to sort n/2 elements, plus n. This is not correct because we are given that the pivot splits the list into two sub-lists, each containing at least one-fifth of the elements. So, the size of the sub-array containing at least one-fifth of the elements is at most 4/5 times the size of the original array. Therefore, the recurrence relation should have a factor of 4/5 instead of 2.

Conclusion:
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Consider the Quicksort algorithm. Suppose there is a procedure for finding a pivot element which splits the list into two sub-lists each of which contains at least one-fifth of the elements. Let T(n) be the number of comparisons required to sort n elements. Thena)T(n) <= 2T(n/5) + nb)T(n) <= T(n/5) + T(4n/5) + nc)T(n) <= 2T(4n/5) + nd)T(n) <= 2T(n/2) + nCorrect answer is option 'B'. Can you explain this answer?
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