For the system 2/s+1, the approximate time taken for a step response t...
Answer: c
Explanation: C(s)/R(s) = 2/s+1
R(s) = 1/s (step input)
C(s) = 2/s(s+1)
c(t) = 2[1-e-t] 1.96 = 2[1-e-T] T= 4sec.
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For the system 2/s+1, the approximate time taken for a step response t...
The given system is a first-order system with a transfer function of 2/s, where 's' represents the Laplace variable. To find the time taken for the step response to reach 98% of its final value, we can analyze the system's response using the time-domain approach.
Step Response Analysis:
The step response of a system is the output when a unit step input is applied to the system. In the Laplace domain, a unit step function is represented as 1/s.
1. Find the Transfer Function:
The transfer function of the given system is 2/s.
2. Determine the Step Response:
To find the step response, we need to multiply the transfer function by the Laplace transform of the unit step function (1/s).
Step response = 2/s * 1/s = 2/s^2
3. Find the Time-Domain Equation:
To convert the Laplace domain equation into the time domain, we can use the inverse Laplace transform. In this case, the inverse Laplace transform of 2/s^2 is a delayed unit step function.
Time-domain equation = 2 * (t - t0)
where 't0' represents the time delay.
4. Determine the Time taken to reach 98% of the Final Value:
To find the time taken for the step response to reach 98% of its final value, we need to determine the value of 't' when the step response equation reaches 0.98 times its final value.
0.98 * (t - t0) = 2 * (t - t0)
Solving the equation, we get:
0.98t - 0.98t0 = 2t - 2t0
0.02t = 0.02t0
t = t0
Since the equation simplifies to t = t0, we can conclude that the time taken for the step response to reach 98% of its final value is equal to the time delay, which is given as 4s in option C.
Therefore, the correct answer is option C (4s).