Which of the following has the maximum number of unpaired electrons? (...
The electronic configuration of the given ions are as follows. 12Mg2+ = 1s2, 2s22p6 (No unpaired electron)
22Ti3+ = 1s2, 2s22p6, 3s23p63d1 (One unpaired electron)
23V3+ = 1s2, 2s22p6, 3s23p63d2 (Two unpaired electrons)
26Fe2+ = 1s2, 2s22p6,3s23p63d6 (Four unpaired electrons)
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Which of the following has the maximum number of unpaired electrons? (...
Explanation:
Unpaired electrons: Unpaired electrons are the electrons in an atom that are not paired with another electron. They are present in the outermost shell of an atom and are involved in chemical bonding and reactions.
Mg2: The atomic number of magnesium (Mg) is 12. It has a configuration of 1s² 2s² 2p⁶ 3s². When it loses two electrons to form the Mg²⁺ ion, the configuration becomes 1s² 2s² 2p⁶. In this configuration, there are no unpaired electrons.
Ti3: The atomic number of titanium (Ti) is 22. It has a configuration of 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d². When it loses three electrons to form the Ti³⁺ ion, the configuration becomes 1s² 2s² 2p⁶ 3s² 3p⁶. In this configuration, there are no unpaired electrons.
V3: The atomic number of vanadium (V) is 23. It has a configuration of 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d³. When it loses three electrons to form the V³⁺ ion, the configuration becomes 1s² 2s² 2p⁶ 3s² 3p⁶. In this configuration, there are no unpaired electrons.
Fe2: The atomic number of iron (Fe) is 26. It has a configuration of 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁶. When it loses two electrons to form the Fe²⁺ ion, the configuration becomes 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁶. In this configuration, there are four unpaired electrons (3d⁶).
Conclusion: Among the given options, Fe²⁺ (option D) has the maximum number of unpaired electrons, which is four.