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Consider any array representation of an n element binary heap where the elements are stored from index 1 to index n of the array. For the element stored at index i of the array (i <= n), the index of the parent is
- a)i - 1
- b)floor(i/2)
- c)(i+1)/2
- d)none
Correct answer is option 'B'. Can you explain this answer?
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Consider any array representation of an n element binary heap where th...
Binary heaps can be represented using arrays: storing elements in an array and using their relative positions within the array to represent child-parent relationships. For the binary heap element stored at index i of the array, Parent Node will be at index: floor(i/2) Left Child will be at index: 2i Right child will be at index: 2*i + 1
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Consider any array representation of an n element binary heap where th...
In a binary heap, for any element stored at index i, the parent of that element is stored at index floor(i/2). So, to find the parent of the element stored at index i, you would calculate floor(i/2).
Similarly, the left child of the element stored at index i is stored at index 2i, and the right child is stored at index 2i + 1. So, to find the left child of the element stored at index i, you would calculate 2i, and to find the right child, you would calculate 2i + 1.
Note that these calculations assume that the binary heap is 1-indexed, meaning that the first element is stored at index 1 and not 0. If the binary heap is 0-indexed, you would need to adjust these calculations accordingly.
Here are the formulas for finding the parent, left child, and right child of an element stored at index i in a 1-indexed binary heap:
Parent: floor(i/2)
Left child: 2i
Right child: 2i + 1
Similarly, the left child of the element stored at index i is stored at index 2i, and the right child is stored at index 2i + 1. So, to find the left child of the element stored at index i, you would calculate 2i, and to find the right child, you would calculate 2i + 1.
Note that these calculations assume that the binary heap is 1-indexed, meaning that the first element is stored at index 1 and not 0. If the binary heap is 0-indexed, you would need to adjust these calculations accordingly.
Here are the formulas for finding the parent, left child, and right child of an element stored at index i in a 1-indexed binary heap:
Parent: floor(i/2)
Left child: 2i
Right child: 2i + 1
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Consider any array representation of an n element binary heap where the elements are stored from index 1 to index n of the array. For the element stored at index i of the array (i <= n), the index of the parent isa)i - 1b)floor(i/2)c)(i+1)/2d)noneCorrect answer is option 'B'. Can you explain this answer?
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