Sum of squares of two numbers is 145. If square root of one number is 3, find the other number.a)136b)9c)64d)8Correct answer is option 'D'. Can you explain this answer?

Question

Answer

X2+ Y2=145
9=3
9×9=81
145-81=64
squire root of 64 =8

Answer

Let X be one number
X^(.5)=3
so
x=9
hence
x^2=81
X^2+Y^2=145
Y^2=64
Y=8

Answer

To solve this problem, we need to use the given information to set up a system of equations and solve for the unknown number.

Let's assume the two numbers are x and y, and we are given the following information:
1) The sum of the squares of the two numbers is 145: x^2 + y^2 = 145
2) The square root of one number is 3: √x = 3

We can use the second piece of information to solve for one of the numbers and substitute it into the first equation.

Solving for x:
√x = 3
Squaring both sides:
x = 3^2
x = 9

Now we can substitute this value of x into the first equation:

9 + y^2 = 145

To solve for y, we can subtract 9 from both sides of the equation:

y^2 = 145 - 9
y^2 = 136

Taking the square root of both sides to isolate y:

√y^2 = √136
y = ±√136

Since we are looking for a specific number, we take the positive square root:

y = √136

Simplifying this square root gives us:

y ≈ 11.66

Therefore, the other number is approximately 11.66.

The correct answer is option D) 8.

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