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The relation
ds = dQ/T
where s represents entropy, Q represents heat and T represents temperature (absolute), holds good in which one of the following processes?
- a)Reversible processes only
- b)Irreversible processes only
- c)Both reversible and irreversible
- d)All real processes
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
The relationds = dQ/Twhere s represents entropy, Q represents heat and...
Explanation:
The relation dQ/T = ds holds good for reversible processes only. Let's understand why it is so.
Reversible processes:
- A reversible process is a process that can be reversed by an infinitesimal change in the conditions.
- It is an ideal process that takes place very slowly and is in equilibrium at every step.
- The system and the surroundings are always in thermal equilibrium.
- The process is said to be quasi-static, i.e. the system remains in equilibrium at every stage.
Irreversible processes:
- An irreversible process is a process that cannot be reversed by an infinitesimal change in the conditions.
- It is a real process that takes place spontaneously and is not in equilibrium at every step.
- The system and the surroundings are not always in thermal equilibrium.
- The process is said to be non-quasi-static, i.e. the system does not remain in equilibrium at every stage.
Relation between dQ, T and ds:
- dQ is the heat transferred between the system and the surroundings. It is a path function, i.e. it depends on the path taken between the initial and final states.
- T is the absolute temperature of the system. It is a state function, i.e. it depends only on the initial and final states.
- ds is the change in entropy of the system. It is a state function, i.e. it depends only on the initial and final states.
Since dQ/T = ds is a state function, it holds good for reversible processes only. In irreversible processes, dQ/T > ds, as there is always some loss of heat to the surroundings.
Conclusion:
Hence, the relation dQ/T = ds holds good for reversible processes only, and not for irreversible processes.
The relation dQ/T = ds holds good for reversible processes only. Let's understand why it is so.
Reversible processes:
- A reversible process is a process that can be reversed by an infinitesimal change in the conditions.
- It is an ideal process that takes place very slowly and is in equilibrium at every step.
- The system and the surroundings are always in thermal equilibrium.
- The process is said to be quasi-static, i.e. the system remains in equilibrium at every stage.
Irreversible processes:
- An irreversible process is a process that cannot be reversed by an infinitesimal change in the conditions.
- It is a real process that takes place spontaneously and is not in equilibrium at every step.
- The system and the surroundings are not always in thermal equilibrium.
- The process is said to be non-quasi-static, i.e. the system does not remain in equilibrium at every stage.
Relation between dQ, T and ds:
- dQ is the heat transferred between the system and the surroundings. It is a path function, i.e. it depends on the path taken between the initial and final states.
- T is the absolute temperature of the system. It is a state function, i.e. it depends only on the initial and final states.
- ds is the change in entropy of the system. It is a state function, i.e. it depends only on the initial and final states.
Since dQ/T = ds is a state function, it holds good for reversible processes only. In irreversible processes, dQ/T > ds, as there is always some loss of heat to the surroundings.
Conclusion:
Hence, the relation dQ/T = ds holds good for reversible processes only, and not for irreversible processes.
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Community Answer
The relationds = dQ/Twhere s represents entropy, Q represents heat and...
Yes answer is right. If process is irreversible then there will be addition of entropy generation. So this formula is not valid for irreversible process
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The relationds = dQ/Twhere s represents entropy, Q represents heat and T represents temperature (absolute), holds good in which one of the following processes?a)Reversible processes onlyb)Irreversible processes onlyc)Both reversible and irreversibled)All real processesCorrect answer is option 'A'. Can you explain this answer?
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