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3 g of activated charcoal was added to 50 mL of acetic acidsolution (0.06N) in a flask. After an hour it was filtered andthe strength of the filtrate was found to be 0.042 N. Theamount of acetic acid adsorbed (per gram of charcoal) is : [JEE M 2015]a)42 mgb)54 mgc)18 mgd)36 mgCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 3 g of activated charcoal was added to 50 mL of acetic acidsolution (0.06N) in a flask. After an hour it was filtered andthe strength of the filtrate was found to be 0.042 N. Theamount of acetic acid adsorbed (per gram of charcoal) is : [JEE M 2015]a)42 mgb)54 mgc)18 mgd)36 mgCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 3 g of activated charcoal was added to 50 mL of acetic acidsolution (0.06N) in a flask. After an hour it was filtered andthe strength of the filtrate was found to be 0.042 N. Theamount of acetic acid adsorbed (per gram of charcoal) is : [JEE M 2015]a)42 mgb)54 mgc)18 mgd)36 mgCorrect answer is option 'C'. Can you explain this answer?.

Solutions for 3 g of activated charcoal was added to 50 mL of acetic acidsolution (0.06N) in a flask. After an hour it was filtered andthe strength of the filtrate was found to be 0.042 N. Theamount of acetic acid adsorbed (per gram of charcoal) is : [JEE M 2015]a)42 mgb)54 mgc)18 mgd)36 mgCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of 3 g of activated charcoal was added to 50 mL of acetic acidsolution (0.06N) in a flask. After an hour it was filtered andthe strength of the filtrate was found to be 0.042 N. Theamount of acetic acid adsorbed (per gram of charcoal) is : [JEE M 2015]a)42 mgb)54 mgc)18 mgd)36 mgCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of 3 g of activated charcoal was added to 50 mL of acetic acidsolution (0.06N) in a flask. After an hour it was filtered andthe strength of the filtrate was found to be 0.042 N. Theamount of acetic acid adsorbed (per gram of charcoal) is : [JEE M 2015]a)42 mgb)54 mgc)18 mgd)36 mgCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for 3 g of activated charcoal was added to 50 mL of acetic acidsolution (0.06N) in a flask. After an hour it was filtered andthe strength of the filtrate was found to be 0.042 N. Theamount of acetic acid adsorbed (per gram of charcoal) is : [JEE M 2015]a)42 mgb)54 mgc)18 mgd)36 mgCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of 3 g of activated charcoal was added to 50 mL of acetic acidsolution (0.06N) in a flask. After an hour it was filtered andthe strength of the filtrate was found to be 0.042 N. Theamount of acetic acid adsorbed (per gram of charcoal) is : [JEE M 2015]a)42 mgb)54 mgc)18 mgd)36 mgCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice 3 g of activated charcoal was added to 50 mL of acetic acidsolution (0.06N) in a flask. After an hour it was filtered andthe strength of the filtrate was found to be 0.042 N. Theamount of acetic acid adsorbed (per gram of charcoal) is : [JEE M 2015]a)42 mgb)54 mgc)18 mgd)36 mgCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.