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A vessel, full of water, weighs 24 kg. When the vessel is 1/4 full, it weighs 9 kg. Find the weight of empty vessel.
- a)4 kg
- b)5 kg
- c)8 kg
- d)3 kg
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A vessel, full of water, weighs 24 kg. When the vessel is1/4 full, it ...
Let ‘x’ be the height of empty vessel and y be the height of full vessel.
x + y = 24.....(1)
x + y/4 = 9....(2)
Solving eq. (1) and (2)
x + y/4 = 9....(2)
Solving eq. (1) and (2)
x = 4 kg
Most Upvoted Answer
A vessel, full of water, weighs 24 kg. When the vessel is1/4 full, it ...
Consider the weight of vessel to be x and the weight of full volume of water to be y.
So, at first instance, x+y=24 (eqn 1)
Next, weight of vessel and one-fourth of water is 9
Hence, x+y/4=9
Multiplying both sides by 4, we get 4x+y=36 (eqn 2)
Subtracting eqn 1 from eqn 2, we will get
x= 4. Hence, option (A) is the correct answer.
So, at first instance, x+y=24 (eqn 1)
Next, weight of vessel and one-fourth of water is 9
Hence, x+y/4=9
Multiplying both sides by 4, we get 4x+y=36 (eqn 2)
Subtracting eqn 1 from eqn 2, we will get
x= 4. Hence, option (A) is the correct answer.
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Community Answer
A vessel, full of water, weighs 24 kg. When the vessel is1/4 full, it ...
Given:
- Weight of vessel when full = 24 kg
- Weight of vessel when 1/4 full = 9 kg
To find:
Weight of empty vessel
Approach:
Let's assume the weight of the empty vessel as 'x' kg.
When the vessel is full, the weight of water it can hold is 24 - x kg.
When the vessel is 1/4 full, the weight of water it can hold is (1/4) * (24 - x) kg.
Calculation:
Given that the weight of the vessel when 1/4 full is 9 kg.
So, (1/4) * (24 - x) = 9
Multiplying both sides of the equation by 4, we get:
24 - x = 36
Subtracting 24 from both sides of the equation, we get:
-x = 12
Multiplying both sides of the equation by -1, we get:
x = -12
Since the weight cannot be negative, the weight of the empty vessel is 12 kg.
Conclusion:
The weight of the empty vessel is 12 kg. Therefore, the correct option is (A) 4 kg.
- Weight of vessel when full = 24 kg
- Weight of vessel when 1/4 full = 9 kg
To find:
Weight of empty vessel
Approach:
Let's assume the weight of the empty vessel as 'x' kg.
When the vessel is full, the weight of water it can hold is 24 - x kg.
When the vessel is 1/4 full, the weight of water it can hold is (1/4) * (24 - x) kg.
Calculation:
Given that the weight of the vessel when 1/4 full is 9 kg.
So, (1/4) * (24 - x) = 9
Multiplying both sides of the equation by 4, we get:
24 - x = 36
Subtracting 24 from both sides of the equation, we get:
-x = 12
Multiplying both sides of the equation by -1, we get:
x = -12
Since the weight cannot be negative, the weight of the empty vessel is 12 kg.
Conclusion:
The weight of the empty vessel is 12 kg. Therefore, the correct option is (A) 4 kg.
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A vessel, full of water, weighs 24 kg. When the vessel is1/4 full, it weighs 9 kg. Find the weight of empty vessel.a)4 kgb)5 kgc)8 kgd)3 kgCorrect answer is option 'A'. Can you explain this answer?
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