A thief steals a car at 3 pm and drives at 75 km/hr. He got discovered...
In one hour thief will travel 75 km. Now let after x distance thief get caught, then
x/75 = (75+x)/100
u will get x = 225, so to travel 225 + 75 = 300 km by police, he will take 3 hours i.e at 7 pm
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A thief steals a car at 3 pm and drives at 75 km/hr. He got discovered...
In one hour thief will travel 75 km. Now let after x distance thief get caught, then
x/75 = (75+x)/100
u will get x = 225, so to travel 225 + 75 = 300 km by police, he will take 3 hours i.e at 7 pm
A thief steals a car at 3 pm and drives at 75 km/hr. He got discovered...
Given:
Speed of thief = 75 km/hr
Speed of police = 100 km/hr
Let's assume that the thief is caught by the police after t hours.
Distance travelled by thief in t hours = 75t km
Distance travelled by police in t-1 hours (as the police discovered the theft after 1 hour) = 100(t-1) km
As they are travelling in opposite directions, the distance between them will decrease at a rate of (75+100) km/hr = 175 km/hr.
Using the formula: Distance = Speed * Time
Distance between thief and police when the police discovered the theft = 0 km
Distance between thief and police at time t = 175t km
Therefore, we can write:
75t + 100(t-1) = 175t
Solving for t, we get:
t = 2
Therefore, the police will catch the thief 2 hours after the theft, i.e. at 7 pm. Hence, option (c) is the correct answer.