Two trees are standing along the opposite sides of a road. Distance be...
In the figure, H is the height of the other tree.
In triangle AEB, AB = 200/tan45°
⇒ AB = 200 mtr
⇒ BC = 400 - 200 = 200 mtr
In triangle DCB, tan 60° = H/BC
⇒ H = 200√3 mtr
∴ Height (in metres) of the other tree = 200√3 mtr
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Two trees are standing along the opposite sides of a road. Distance be...
And 60 degrees. Let's call the height of the first tree h1 and the height of the second tree h2.
Using the given angles of depression, we can form two right triangles. The first triangle consists of the first tree, the point, and the line connecting the first tree to the point. The second triangle consists of the second tree, the point, and the line connecting the second tree to the point.
In the first triangle, the angle of depression is 45 degrees. This means that the angle opposite to the line connecting the first tree to the point is also 45 degrees. Since the angle opposite a 45-degree angle in a right triangle is also 45 degrees, the first triangle is an isosceles right triangle.
Similarly, in the second triangle, the angle of depression is 60 degrees. This means that the angle opposite to the line connecting the second tree to the point is also 60 degrees. Since the angle opposite a 60-degree angle in a right triangle is also 30 degrees, the second triangle is a 30-60-90 triangle.
Now, let's analyze each triangle separately:
First Triangle (45-45-90):
Since the first triangle is isosceles, the two legs of the triangle are congruent. Let's call the length of each leg x. The hypotenuse of the triangle will be 400 - x (as the distance between the trees is 400 meters). In a 45-45-90 triangle, the ratio of the lengths of the legs to the hypotenuse is 1:1:√2.
So, in this triangle, we have:
h1 = x
400 - x = x√2
Simplifying the second equation:
400 = x(√2 + 1)
400/√2 + 400 = x
Therefore, h1 = x = 400/√2 + 400 ≈ 850.85 meters.
Second Triangle (30-60-90):
In a 30-60-90 triangle, the ratio of the lengths of the sides opposite to the angles is 1:√3:2.
In this triangle, we have:
h2 = x√3 (since the line connecting the second tree to the point is opposite the 60-degree angle)
400 - x = 2x√3 (since the line connecting the second tree to the point is opposite the 30-degree angle)
Simplifying the second equation:
400 = 2x√3 + x
400 = x(2√3 + 1)
400/(2√3 + 1) = x
Therefore, h2 = x√3 = 400/(2√3 + 1) ≈ 275.77 meters.
So, the height of the first tree (h1) is approximately 850.85 meters and the height of the second tree (h2) is approximately 275.77 meters.
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