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The ammonia evolved from the treatment of 0.30 g of an organic compound for the estimation of nitrogen was passed in 100 mL of 0.1 M sulphuric acid. The excess of acid required 20 mL of 0.5 M sodium hydroxide solution for complete neutralization. The organic compound is [2004]
  • a)
    urea
  • b)
    benzamide
  • c)
    acetamide
  • d)
    thiourea
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The ammonia evolved from the treatment of 0.30 g of an organic compoun...
H2SO4 is dibasic. 0.1 M H2SO4 = 0.2N H2SO4 [ ∵ M = 2xN ]
Meq of H2SO4 taken = = 100 x 0.2 = 20
Meq of H2SO4 neutralised by NaOH = 20 x 0.5 = 10
Meq of H2SO4 neutralised by NH3  = 20 – 10 = 10
% of  N
= 46.6
% of nitrogen in urea= 46.6
[Mol.wt of urea =60]
Similarly % of Nitrogen in Benzamide
= 11.5%   [C6H5CONH2 = 121]
Acetamide  = = 23.4%  [ CH3CONH= 59]
Thiourea =  = 36.8%  [NH2CSNH2 = 76]
Hence the compound must be urea.
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The ammonia evolved from the treatment of 0.30 g of an organic compound for the estimation of nitrogen was passed in 100 mL of 0.1 M sulphuric acid. The excess of acid required 20 mL of 0.5 M sodium hydroxide solution for complete neutralization. The organic compound is [2004]a)ureab)benzamidec)acetamided)thioureaCorrect answer is option 'A'. Can you explain this answer?
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