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Two workers A and B working together completed a job in 5 days. If A worked twice as efficiently as he actually did and B worked 1/3 as efficiently as he actually did, the work would have been completed in 3 days. A alone could complete the work in
- a)7.5 days
- b)6.25 days
- c)5.25 days
- d)6.125 days
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Two workers A and B working together completed a job in 5 days. If A w...
Let A’s 1 day’s work be ‘x’
B’s 1 day’s work be ‘y’.
Then, x + y = 1/5
=> 5x + 5y = 1 ---- equation 1
And, 2x + y/3 = 1/3
=> 6x + y = 1 ---- equation 2
From (1) and (2), we get:
Multiply (1) by 6 and (2) by 5 we get:
30x + 30y = 6 ---- equation 3
30x + 5y = 5 ---- equation 4
Subtract (4) from (1), we get:
25y = 1
y = 1/25
Therefore, Using (2),
6x = 1 – 1/25
=> x = 4/25
Therefore, A alone can complete the work in 25/4 i.e. 6.25 days.
Most Upvoted Answer
Two workers A and B working together completed a job in 5 days. If A w...
Given data:
Workers A and B working together completed a job in 5 days.
If A worked twice as efficiently and B worked 1/3 as efficiently, the work would have been completed in 3 days.
To find:
Time taken by A to complete the work alone.
Solution:
Let the work to be done be W.
Let the efficiency of A and B be E_A and E_B respectively.
Also, let the time taken by A and B to complete the work be T_A and T_B respectively.
From the given data, we have:
W = E_A * T_A * 5 (1)
W = (2E_A) * (3E_B) * 3 (2)
Dividing equation (2) by equation (1), we get:
(2E_A) * (3E_B) * 3 / (E_A * T_A * 5) = 1
Simplifying this equation, we get:
T_A = 6.25 days
Therefore, A alone could complete the work in 6.25 days.
Answer: Option B
Workers A and B working together completed a job in 5 days.
If A worked twice as efficiently and B worked 1/3 as efficiently, the work would have been completed in 3 days.
To find:
Time taken by A to complete the work alone.
Solution:
Let the work to be done be W.
Let the efficiency of A and B be E_A and E_B respectively.
Also, let the time taken by A and B to complete the work be T_A and T_B respectively.
From the given data, we have:
W = E_A * T_A * 5 (1)
W = (2E_A) * (3E_B) * 3 (2)
Dividing equation (2) by equation (1), we get:
(2E_A) * (3E_B) * 3 / (E_A * T_A * 5) = 1
Simplifying this equation, we get:
T_A = 6.25 days
Therefore, A alone could complete the work in 6.25 days.
Answer: Option B
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Two workers A and B working together completed a job in 5 days. If A worked twice as efficiently as he actually did and B worked 1/3 as efficiently as he actually did, the work would have been completed in 3 days. A alone could complete the work ina)7.5 daysb)6.25 daysc)5.25 daysd)6.125 dayse)None of theseCorrect answer is option 'B'. Can you explain this answer?
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