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The standard sea level atmospheric pressure is equivalent to
  • a)
    10.2 m of freshwater of density (ρ) = 998 kg/m3
  • b)
    10.1 m of saline water of density (ρ) = 1025 kg/m3
  • c)
    12.5 m of kerosene of density (ρ) = 800 kg/m3
  • d)
    • 6.4 m of carbon tetrachloride of density (ρ) = 1590 kg/m3
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The standard sea level atmospheric pressure is equivalent toa)10.2 m o...
Pressure at sea level = 101.325 kPa
Checking according to given options.
P = hρg
a) ⇒ 10.2 m of fresh water (ρ = 998 kg/m3)
P = 10.2 × 998 × 9.81 = 99861.87 Pa = 99.861 kPa
b) ⇒ 10.1 m of saline water (ρ = 1025 kg/m3)
P = 10.1 × 1025 × 9.81 = 101.558 kPa
c) ⇒ 12.5 m of kerosene of ρ = 800 kg/m3
P = 12.5 × 800 × 9.81 = 98.1 kPa
d) ⇒ 6.4 m of carbon tetrachloride of ρ = 1590 kg/m3
⇒ 6.4 × 1590 × 9.81 = 99.826 kPa
So option b is nearest, so correct
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Most Upvoted Answer
The standard sea level atmospheric pressure is equivalent toa)10.2 m o...
1000 kg/m³) b)10.2 m of seawater of density (1025 kg/m³) c)10.3 m of freshwater of density (1000 kg/m³) d)10.3 m of seawater of density (1025 kg/m³)

Answer: c) 10.3 m of freshwater of density (1000 kg/m³)

Explanation: The standard sea level atmospheric pressure is defined as 1013.25 millibars (mb) or 1 atmosphere (atm). This is equivalent to a pressure of 1.01325 × 10⁵ Pa. Using the formula for hydrostatic pressure, we can calculate the height of a column of fluid that would exert this pressure:

P = ρgh

where P is the pressure, ρ is the density of the fluid, g is the acceleration due to gravity (9.81 m/s²), and h is the height of the column.

For freshwater with a density of 1000 kg/m³, we can solve for h:

1.01325 × 10⁵ Pa = 1000 kg/m³ × 9.81 m/s² × h

h = 1.01325 × 10⁵ Pa / (1000 kg/m³ × 9.81 m/s²) ≈ 10.3 m

Therefore, the standard sea level atmospheric pressure is equivalent to a column of freshwater with a height of approximately 10.3 meters.
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The standard sea level atmospheric pressure is equivalent toa)10.2 m of freshwater of density (ρ) = 998 kg/m3b)10.1 m of saline water ofdensity (ρ)= 1025 kg/m3c)12.5 m of kerosene of density (ρ) = 800 kg/m3d) 6.4 m of carbon tetrachloride of density (ρ) = 1590 kg/m3 Correct answer is option 'B'. Can you explain this answer?
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