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The product of three terms in G. P is 125/8, find G. M ?
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The product of three terms in G. P is 125/8, find G. M ?
Problem: The product of three terms in G. P is 125/8, find G. M?

Solution:

Let the three terms in the G.P be a, ar and ar^2

Then, their product is: a * ar * ar^2 = a^3r^3

Given, a^3r^3 = 125/8

Taking cube root on both sides, we get:

ar = (125/8)^(1/3) = 5/2

Also, ar^2 = (ar) * ar = (5/2) * ar = (5/2)^2

Therefore, r = ar/ar = (5/2) / 1 = 5/2

Now, we can find the second term of the G.P (i.e., ar) as 5/2.

Finally, we can find the G.M (i.e., geometric mean) of the three terms in the G.P as:

G.M = (a * ar * ar^2)^(1/3) = [a * (5/2) * (25/4)]^(1/3) = (125a/8)^(1/3)

Hence, we have found the G.M of the three terms in the G.P as (125a/8)^(1/3).

Conclusion: The G.M of the three terms in the G.P is (125a/8)^(1/3).
Community Answer
The product of three terms in G. P is 125/8, find G. M ?
Let GM be a and common ratio be r
The terms will be a/r ,a ,ar
(a/r)(a)(ar)=125/8
a×a×a=125/8
a=5/2
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The product of three terms in G. P is 125/8, find G. M ?
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