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Neopentyl alcohol on treatment with HBr gives
- a)neopentyl bromide
- b)2- bromo -2- methylbutane
- c)2- methyl -2- butane
- d)2- methyl 1- butene
Correct answer is option 'B'. Can you explain this answer?
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Formation of 2-bromo-2-methylbutane from neopentyl alcohol and HBr
The reaction between neopentyl alcohol and HBr proceeds via an SN1 mechanism, which involves the following steps:
1. Protonation of the alcohol: HBr acts as a proton donor and protonates the oxygen atom of the alcohol to form a more reactive intermediate, neopentyl oxonium ion.
2. Formation of a carbocation: The oxonium ion undergoes heterolysis to form a carbocation intermediate, which is stabilized by the three methyl groups surrounding it.
3. Nucleophilic attack: Br- acts as a nucleophile and attacks the carbocation, leading to the formation of 2-bromo-2-methylbutane.
Thus, the correct answer is option B, 2-bromo-2-methylbutane.
The reaction between neopentyl alcohol and HBr proceeds via an SN1 mechanism, which involves the following steps:
1. Protonation of the alcohol: HBr acts as a proton donor and protonates the oxygen atom of the alcohol to form a more reactive intermediate, neopentyl oxonium ion.
2. Formation of a carbocation: The oxonium ion undergoes heterolysis to form a carbocation intermediate, which is stabilized by the three methyl groups surrounding it.
3. Nucleophilic attack: Br- acts as a nucleophile and attacks the carbocation, leading to the formation of 2-bromo-2-methylbutane.
Thus, the correct answer is option B, 2-bromo-2-methylbutane.
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Neopentyl alcohol on treatment with HBr gives a)neopentyl bromideb)2- bromo -2- methylbutane c)2- methyl -2- butaned)2- methyl 1- butene Correct answer is option 'B'. Can you explain this answer?
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