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The edge length of a face centred cubic cell of an ionic substance is 508 pm. If the radius of the cation is 110 pm, the radius of the anion is
  • a)
    288 pm
  • b)
    144 pm
  • c)
    618 pm
  • d)
    398 pm
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The edge length of a face centred cubic cell of an ionic substance is ...
Given:
Edge length of a face-centred cubic cell = 508 pm
Radius of cation = 110 pm

To find: Radius of anion

Formula used:
In a face-centred cubic cell, the cation is present at the corners of the cube and the face-centred positions, while the anion is present at the centre of each face of the cube.

Let the radius of the anion be 'r'.
The edge length of the face-centred cubic cell (a) can be given as:
a = 4r/sqrt(2)

Calculation:
Given, edge length of the face-centred cubic cell = 508 pm
Therefore, a = 508 pm

Substituting the value of 'a' in the above equation, we get:
508 = 4r/sqrt(2)
r = 508 x sqrt(2)/4
r = 254 x sqrt(2) pm
r = 254 x 1.414 pm
r = 359 pm

Therefore, the radius of the anion is 359 pm.

Answer:
The correct option is not given in the question. The calculated value of the radius of the anion is 359 pm.
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The edge length of a face centred cubic cell of an ionic substance is ...
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The edge length of a face centred cubic cell of an ionic substance is 508 pm. If the radius of the cation is 110 pm, the radius of the anion isa)288 pmb)144 pmc)618 pmd)398 pmCorrect answer is option 'B'. Can you explain this answer?
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