An object is placed at a distance u from a concave mirror and its real image is received on a screen placed at a distance of v from the mirror. If f is the focal length of the mirror, then the graph between 1/v versus 1/u isa)b)c)d)Correct answer is option 'B'. Can you explain this answer?

Question

Answer

1/f =1/v+1/u

1/v=1/f-1/u

Hence the graph of 1/v against 1/u would have equal intercepts on their +ve axes(=1/f) and is negative sloping.

Hence option B is most correct.

Answer

For real object and real Image,
(1/v)+(1/u)=(1/f)=> -(1/v)-(1/u)=-(1/f)
(1/v)+(1/u)=(1/f) => 1/v=-(1/u)+(1/f)
y=mx+c
The correct answer is option B.

Answer

For real object and real Image,
(1/v)+(1/u)=(1/f)=> -(1/v)-(1/u)=-(1/f)
(1/v)+(1/u)=(1/f) => 1/v=-(1/u)+(1/f)
y=mx+c
The correct answer is option B.

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