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A steel rod of 1 sq. cm. cross sectional area is 100 cm long and has a Young’s modulus of elasticity 2 × 106 kgf/cm2. It is subjected to an axial pull of 2000 kgf. The elongation of the rod will be
  • a)
    0.05 cm
  • b)
    0.1 cm
  • c)
    0.15 cm
  • d)
    0.20 cm
Correct answer is option 'B'. Can you explain this answer?
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A steel rod of 1 sq. cm. cross sectional area is 100 cm long and has a...
Change in length:
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A steel rod of 1 sq. cm. cross sectional area is 100 cm long and has a...
's modulus of 2.0 × 10^11 N/m^2. Calculate the force required to stretch the rod by 0.1 cm.

We can use the formula for Young's modulus:

stress = (force/area) = (Young's modulus) × (strain)

where strain is the fractional change in length, given by:

strain = (change in length/original length)

In this case, the change in length is 0.1 cm and the original length is 100 cm, so:

strain = 0.1 cm / 100 cm = 0.001

Substituting into the first equation, we get:

force/1 sq. cm = (2.0 × 10^11 N/m^2) × 0.001

Simplifying:

force = (2.0 × 10^11 N/m^2) × 0.001 sq. m × 1 sq. cm

force = 2.0 × 10^8 N

Therefore, the force required to stretch the rod by 0.1 cm is 2.0 × 10^8 N.
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A steel rod of 1 sq. cm. cross sectional area is 100 cm long and has a Young’s modulus of elasticity 2 × 106kgf/cm2. It is subjected to an axial pull of 2000 kgf. The elongation of the rod will bea)0.05 cmb)0.1 cmc)0.15 cmd)0.20 cmCorrect answer is option 'B'. Can you explain this answer?
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