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Of the 5 subjects, the average marks of Rakesh in first 3 Subjects was 79 and the average marks in the last 3 subjects was 86. If his marks in the third subject were 80, then what were his average marks in all the 5 subjects?
  • a)
    81
  • b)
    82
  • c)
    83
  • d)
    85
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Of the 5 subjects, the average marks of Rakesh in first 3 Subjects was...
We know,
Average = sum of all observations/number of observations
⇒ Average marks of Rakesh in first 3 subjects = 79
⇒ Sum of marks in first 3 subjects = 79 × 3 = 237
Also,
Average marks of Rakesh in last 3 subjects = 86
⇒ Sum of marks in last 3 subjects = 86 × 3 = 258
Marks in third subject = 80
Sum of marks in all the five subjects = 237 + 258 - 80 = 415
∴ Average of all the five subjects = 415/5 = 83
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Most Upvoted Answer
Of the 5 subjects, the average marks of Rakesh in first 3 Subjects was...
Given information:
- Rakesh has 5 subjects.
- The average marks in the first 3 subjects is 79.
- The average marks in the last 3 subjects is 86.
- Rakesh scored 80 marks in the third subject.

To find:
What were Rakesh's average marks in all 5 subjects?

Solution:
Let's denote the marks in the first subject as x, the marks in the second subject as y, and the marks in the fourth and fifth subjects as a and b, respectively.

Average of the first 3 subjects:
- The sum of the marks in the first 3 subjects is x + y + 80.
- The average of the first 3 subjects is (x + y + 80)/3.
- The average of the first 3 subjects is given as 79.
Therefore, (x + y + 80)/3 = 79.

Average of the last 3 subjects:
- The sum of the marks in the last 3 subjects is 80 + a + b.
- The average of the last 3 subjects is (80 + a + b)/3.
- The average of the last 3 subjects is given as 86.
Therefore, (80 + a + b)/3 = 86.

Solving the equations:
- From the first equation, we have x + y + 80 = 237. (Multiplying both sides by 3)
- From the second equation, we have 80 + a + b = 258. (Multiplying both sides by 3)

Finding the values of x, y, a, and b:
- Subtracting 80 from both sides of the first equation, we get x + y = 157.
- Subtracting 80 from both sides of the second equation, we get a + b = 178.

Finding the average of all 5 subjects:
- The sum of the marks in all 5 subjects is x + y + 80 + a + b.
- Substituting the values of x + y and a + b, we get 157 + 80 + 178 = 415.
- The average of all 5 subjects is (x + y + 80 + a + b)/5.
- Substituting the value of the sum, we get 415/5 = 83.

Therefore, Rakesh's average marks in all 5 subjects is 83. Hence, the correct answer is option C.
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Of the 5 subjects, the average marks of Rakesh in first 3 Subjects was 79 and the average marks in the last 3 subjects was 86. If his marks in the third subject were 80, then what were his average marks in all the 5 subjects?a)81b)82c)83d)85Correct answer is option 'C'. Can you explain this answer?
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Of the 5 subjects, the average marks of Rakesh in first 3 Subjects was 79 and the average marks in the last 3 subjects was 86. If his marks in the third subject were 80, then what were his average marks in all the 5 subjects?a)81b)82c)83d)85Correct answer is option 'C'. Can you explain this answer? for Railways 2024 is part of Railways preparation. The Question and answers have been prepared according to the Railways exam syllabus. Information about Of the 5 subjects, the average marks of Rakesh in first 3 Subjects was 79 and the average marks in the last 3 subjects was 86. If his marks in the third subject were 80, then what were his average marks in all the 5 subjects?a)81b)82c)83d)85Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Railways 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Of the 5 subjects, the average marks of Rakesh in first 3 Subjects was 79 and the average marks in the last 3 subjects was 86. If his marks in the third subject were 80, then what were his average marks in all the 5 subjects?a)81b)82c)83d)85Correct answer is option 'C'. Can you explain this answer?.
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