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One hundred identical coins, each with probability, p, of showing up heads are tossed once. If 0 < p < 1 and the probabilitity of heads showing on 50 coins is equal to that of heads showing on 51 coins, then the value of p is (1988 - 2 Marks)
  • a)
    1/2
  • b)
    49/101
  • c)
    50/101
  • d)
    51/101.
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
One hundred identical coins, each with probability, p, of showing up h...
Prob. of one coin showing head = p
∴ Prob of one coin showing tail = 1– p ATQ coin is tossed 100 times and prob. of 50 coins showing head = prob of 51 coins showing head.
Using binomial prob. distribution
P (X = r)= nCr prqn-r ,
we get,    
⇒ 51 – 51 p = 50 p
⇒ 101 p = 51 ⇒ 
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One hundred identical coins, each with probability, p, of showing up heads are tossed once. If 0 < p < 1 and the probabilitity of heads showing on 50 coins is equal to that of heads showing on 51 coins, then the value of p is (1988 - 2 Marks)a)1/2b)49/101c)50/101d)51/101.Correct answer is option 'D'. Can you explain this answer?
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One hundred identical coins, each with probability, p, of showing up heads are tossed once. If 0 < p < 1 and the probabilitity of heads showing on 50 coins is equal to that of heads showing on 51 coins, then the value of p is (1988 - 2 Marks)a)1/2b)49/101c)50/101d)51/101.Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about One hundred identical coins, each with probability, p, of showing up heads are tossed once. If 0 < p < 1 and the probabilitity of heads showing on 50 coins is equal to that of heads showing on 51 coins, then the value of p is (1988 - 2 Marks)a)1/2b)49/101c)50/101d)51/101.Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One hundred identical coins, each with probability, p, of showing up heads are tossed once. If 0 < p < 1 and the probabilitity of heads showing on 50 coins is equal to that of heads showing on 51 coins, then the value of p is (1988 - 2 Marks)a)1/2b)49/101c)50/101d)51/101.Correct answer is option 'D'. Can you explain this answer?.
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