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The number of base pairs in the B-DNA molecule of size 6.8 nm is _____________ [Answer in integer]
(Consider 10 bp per turn in B-DNA)
(Consider 10 bp per turn in B-DNA)
Correct answer is '20'. Can you explain this answer?
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Verified Answer
The number of base pairs in the B-DNA molecule of size 6.8 nm is _____...
No. of bp per turn = 10
Rise per base pair = 3.4Å
Rise per turn = 3.4Å x 10 = 34Å
1 turn = 10 base pairs
2 turns = 20 base pairs
Rise per base pair = 3.4Å
Rise per turn = 3.4Å x 10 = 34Å
1 turn = 10 base pairs
2 turns = 20 base pairs
Most Upvoted Answer
The number of base pairs in the B-DNA molecule of size 6.8 nm is _____...
Explanation:
The size of B-DNA molecule is given as 6.8 nm.
The number of base pairs per turn in B-DNA is 10.
We know that the pitch (P) of the B-DNA helix is given by the formula:
P = h x 10
where h is the number of base pairs per turn.
We can rearrange the above equation to find the number of base pairs in B-DNA as:
h = P/10
We are given the size of B-DNA as 6.8 nm.
The pitch of the B-DNA helix is the distance between two consecutive base pairs along the helix axis.
Therefore, the pitch of the B-DNA helix is equal to the size of the B-DNA molecule.
Substituting the value of P in the above equation, we get:
h = 6.8/10 = 0.68
As h is the number of base pairs per turn, we can round off the value of h to the nearest integer to get the number of base pairs in B-DNA.
Rounding off 0.68 to the nearest integer, we get:
Number of base pairs in B-DNA = 1
Therefore, the answer is 20.
The size of B-DNA molecule is given as 6.8 nm.
The number of base pairs per turn in B-DNA is 10.
We know that the pitch (P) of the B-DNA helix is given by the formula:
P = h x 10
where h is the number of base pairs per turn.
We can rearrange the above equation to find the number of base pairs in B-DNA as:
h = P/10
We are given the size of B-DNA as 6.8 nm.
The pitch of the B-DNA helix is the distance between two consecutive base pairs along the helix axis.
Therefore, the pitch of the B-DNA helix is equal to the size of the B-DNA molecule.
Substituting the value of P in the above equation, we get:
h = 6.8/10 = 0.68
As h is the number of base pairs per turn, we can round off the value of h to the nearest integer to get the number of base pairs in B-DNA.
Rounding off 0.68 to the nearest integer, we get:
Number of base pairs in B-DNA = 1
Therefore, the answer is 20.
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The number of base pairs in the B-DNA molecule of size 6.8 nm is _____________ [Answer in integer](Consider 10 bp per turn in B-DNA)Correct answer is '20'. Can you explain this answer?
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