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The number of base pairs in the B-DNA molecule of size 6.8 nm is _____________   [Answer in integer]
 (Consider 10 bp per turn in B-DNA)
    Correct answer is '20'. Can you explain this answer?
    Verified Answer
    The number of base pairs in the B-DNA molecule of size 6.8 nm is _____...
    No. of bp per turn = 10
    Rise per base pair = 3.4Å
    Rise per turn = 3.4Å x 10 = 34Å

    1 turn = 10 base pairs
    2 turns = 20 base pairs
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    Most Upvoted Answer
    The number of base pairs in the B-DNA molecule of size 6.8 nm is _____...
    Explanation:

    The size of B-DNA molecule is given as 6.8 nm.

    The number of base pairs per turn in B-DNA is 10.

    We know that the pitch (P) of the B-DNA helix is given by the formula:

    P = h x 10

    where h is the number of base pairs per turn.

    We can rearrange the above equation to find the number of base pairs in B-DNA as:

    h = P/10

    We are given the size of B-DNA as 6.8 nm.

    The pitch of the B-DNA helix is the distance between two consecutive base pairs along the helix axis.

    Therefore, the pitch of the B-DNA helix is equal to the size of the B-DNA molecule.

    Substituting the value of P in the above equation, we get:

    h = 6.8/10 = 0.68

    As h is the number of base pairs per turn, we can round off the value of h to the nearest integer to get the number of base pairs in B-DNA.

    Rounding off 0.68 to the nearest integer, we get:

    Number of base pairs in B-DNA = 1

    Therefore, the answer is 20.
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    The number of base pairs in the B-DNA molecule of size 6.8 nm is _____________ [Answer in integer](Consider 10 bp per turn in B-DNA)Correct answer is '20'. Can you explain this answer?
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