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A 250 mg sample of pure oil requires 47.5 mg of KOH for complete saponification. The average MW of the triglycerides in the olive oil is________. (Answer in integer)
Correct answer is '884'. Can you explain this answer?
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Verified Answer
A 250 mg sample of pure oil requires 47.5 mg of KOH for complete sapon...
Amount of KOH required = 47.5 x 10-3/ 56g mole = 8.482 x 10-4 moles
It takes 3 moles of KOH for each mole of triglyceride
Amount of triglyceride present = 8.482 x 10-4/3 = 2.828 x 10-4moles
No. of moles = wt/MW or MW = wt/no. of moles
MW = 250 x 10-5/2.827 x 104 = 884
It takes 3 moles of KOH for each mole of triglyceride
Amount of triglyceride present = 8.482 x 10-4/3 = 2.828 x 10-4moles
No. of moles = wt/MW or MW = wt/no. of moles
MW = 250 x 10-5/2.827 x 104 = 884
Most Upvoted Answer
A 250 mg sample of pure oil requires 47.5 mg of KOH for complete sapon...
Given Information:
- Sample size: 250 mg
- KOH required for saponification: 47.5 mg
Formula:
The saponification value (SV) is the amount of KOH required for the complete saponification of a given weight of fat or oil. It is expressed in mg of KOH per gram of fat or oil.
Calculation:
To find the average molecular weight (MW) of the triglycerides in the olive oil, we need to use the saponification value.
1. Calculate the saponification value (SV):
SV = (Weight of KOH / Weight of oil) * 1000 mg/g
SV = (47.5 mg / 250 mg) * 1000 mg/g
SV = 190 mg/g
2. Calculate the molecular weight (MW) using the saponification value:
MW = (SV / 56.1) * 1000 g/mol
MW = (190 mg/g / 56.1) * 1000 g/mol
MW ≈ 3388.4 g/mol
3. Convert the molecular weight from g/mol to integer:
MW ≈ 3388.4 g/mol ≈ 3388 g/mol ≈ 3388
Answer:
The average molecular weight (MW) of the triglycerides in the olive oil is approximately 3388 g/mol, which rounds to 3388.
- Sample size: 250 mg
- KOH required for saponification: 47.5 mg
Formula:
The saponification value (SV) is the amount of KOH required for the complete saponification of a given weight of fat or oil. It is expressed in mg of KOH per gram of fat or oil.
Calculation:
To find the average molecular weight (MW) of the triglycerides in the olive oil, we need to use the saponification value.
1. Calculate the saponification value (SV):
SV = (Weight of KOH / Weight of oil) * 1000 mg/g
SV = (47.5 mg / 250 mg) * 1000 mg/g
SV = 190 mg/g
2. Calculate the molecular weight (MW) using the saponification value:
MW = (SV / 56.1) * 1000 g/mol
MW = (190 mg/g / 56.1) * 1000 g/mol
MW ≈ 3388.4 g/mol
3. Convert the molecular weight from g/mol to integer:
MW ≈ 3388.4 g/mol ≈ 3388 g/mol ≈ 3388
Answer:
The average molecular weight (MW) of the triglycerides in the olive oil is approximately 3388 g/mol, which rounds to 3388.
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A 250 mg sample of pure oil requires 47.5 mg of KOH for complete saponification. The average MW of the triglycerides in the olive oil is________. (Answer in integer)Correct answer is '884'. Can you explain this answer?
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A 250 mg sample of pure oil requires 47.5 mg of KOH for complete saponification. The average MW of the triglycerides in the olive oil is________. (Answer in integer)Correct answer is '884'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about A 250 mg sample of pure oil requires 47.5 mg of KOH for complete saponification. The average MW of the triglycerides in the olive oil is________. (Answer in integer)Correct answer is '884'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 250 mg sample of pure oil requires 47.5 mg of KOH for complete saponification. The average MW of the triglycerides in the olive oil is________. (Answer in integer)Correct answer is '884'. Can you explain this answer?.
A 250 mg sample of pure oil requires 47.5 mg of KOH for complete saponification. The average MW of the triglycerides in the olive oil is________. (Answer in integer)Correct answer is '884'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about A 250 mg sample of pure oil requires 47.5 mg of KOH for complete saponification. The average MW of the triglycerides in the olive oil is________. (Answer in integer)Correct answer is '884'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 250 mg sample of pure oil requires 47.5 mg of KOH for complete saponification. The average MW of the triglycerides in the olive oil is________. (Answer in integer)Correct answer is '884'. Can you explain this answer?.
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