The olive oil was reacted with iodine. The average MW of triglycerides...
0.578 g of I2/0.680 g oil = Wt I2/894 g oil
Wt I2 absorbed = (884)(0.578)/(0.680) = 751.4 g I2 per mole of oil
MW of I2 = (2) (126.9) = 253.8
751.4 g I2 / 253.8 g/mole = 2.96 moles I2/mole of oil
Thus on average there are three double bond per molecule of triglyceride.
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The olive oil was reacted with iodine. The average MW of triglycerides...
Given Information:
- The average molecular weight (MW) of triglycerides present in the olive oil is 884 g.
- 578 mg of I2 were absorbed by 680 mg of the oil.
Calculating the Number of Moles of I2:
To determine the number of double bonds in the triglycerides, we need to find the number of moles of I2 that reacted with the oil.
Given:
- Mass of I2 absorbed = 578 mg
- Mass of oil = 680 mg
To find the number of moles of I2, we need to convert the mass of I2 to moles using its molar mass.
Molar mass of I2 = 253.8 g/mol
Number of moles of I2 = (Mass of I2 absorbed / Molar mass of I2)
= (578 mg / 253.8 g/mol)
= 0.00228 mol
Calculating the Number of Moles of Triglycerides:
To determine the number of moles of triglycerides, we can use the average molecular weight of triglycerides present in the olive oil.
Given:
- Average MW of triglycerides = 884 g
Number of moles of triglycerides = (Mass of oil / Average MW of triglycerides)
= (680 mg / 884 g/mol)
= 0.769 mol
Calculating the Number of Double Bonds:
The reaction between iodine and double bonds in triglycerides is known as the iodine value test. In this test, one mole of I2 reacts with two moles of double bonds.
From the given information, we know that 0.00228 mol of I2 reacted with 0.769 mol of triglycerides. Therefore, the ratio of moles of I2 to moles of triglycerides is 0.00228:0.769, which can be simplified to 1:337.5.
Since one mole of I2 reacts with two moles of double bonds, the ratio of moles of double bonds to moles of triglycerides is 2:1.
Therefore, the number of moles of double bonds = (0.769 mol / 2)
= 0.3845 mol
Final Answer:
The average number of double bonds present in a molecule of triglyceride is approximately 0.3845. Since the answer should be an integer, rounding up the value gives us 1. Therefore, the correct answer is 1.