IIT JAM Exam  >  IIT JAM Questions  >  Elemental analysis of an organic compound con... Start Learning for Free
Elemental analysis of an organic compound containing C, H and O gives percentage composition: C: 39.9 % and H: 6.7 %. If the molecular weight of the compound is 180, the number of carbon atoms present in the molecule is________.
    Correct answer is between '6,6'. Can you explain this answer?
    Most Upvoted Answer
    Elemental analysis of an organic compound containing C, H and O gives ...
    Given:
    Percentage composition of C: 39.9%
    Percentage composition of H: 6.7%
    Molecular weight of the compound: 180

    To find: Number of carbon atoms present in the molecule.

    Let's assume the number of carbon atoms in the molecule is x.

    1. Calculation of the number of carbon atoms:
    The percentage composition of carbon (C) in the compound is given as 39.9%. This means that the compound contains 39.9 grams of carbon for every 100 grams of the compound.

    To calculate the number of carbon atoms, we need to convert the percentage into grams. The molar mass of carbon (C) is 12 g/mol.

    The number of moles of carbon (C) in the compound can be calculated using the formula:
    moles = (mass of element / molar mass of element)

    Therefore, the number of moles of carbon (C) can be calculated as:
    moles of carbon (C) = (39.9 g / 12 g/mol) = 3.325 mol

    Since 1 mol of carbon (C) contains Avogadro's number (6.022 x 10^23) of atoms, the number of carbon atoms (x) can be calculated as:
    x = (3.325 mol) x (6.022 x 10^23 atoms/mol) = 2.00 x 10^24 atoms

    2. Calculation of the number of hydrogen atoms:
    The percentage composition of hydrogen (H) in the compound is given as 6.7%. This means that the compound contains 6.7 grams of hydrogen for every 100 grams of the compound.

    To calculate the number of hydrogen atoms, we need to convert the percentage into grams. The molar mass of hydrogen (H) is 1 g/mol.

    The number of moles of hydrogen (H) in the compound can be calculated using the formula:
    moles = (mass of element / molar mass of element)

    Therefore, the number of moles of hydrogen (H) can be calculated as:
    moles of hydrogen (H) = (6.7 g / 1 g/mol) = 6.7 mol

    Since 1 mol of hydrogen (H) contains Avogadro's number (6.022 x 10^23) of atoms, the number of hydrogen atoms can be calculated as:
    Number of hydrogen atoms = (6.7 mol) x (6.022 x 10^23 atoms/mol) = 4.03 x 10^24 atoms

    3. Calculation of the number of oxygen atoms:
    The total percentage composition of all elements in a compound is equal to 100%. Therefore, the percentage composition of oxygen (O) can be calculated as:
    Percentage of oxygen (O) = 100% - (Percentage of carbon (C) + Percentage of hydrogen (H))
    Percentage of oxygen (O) = 100% - (39.9% + 6.7%) = 53.4%

    Since the molecular weight of the compound is 180 g/mol, the mass of oxygen (O) in the compound can be calculated as:
    mass of oxygen (O) = (Percentage of oxygen (O) / 100) x Molecular weight of the compound
    mass of oxygen (O) = (53.4 / 100) x 180 g = 96.12 g

    The
    Free Test
    Community Answer
    Elemental analysis of an organic compound containing C, H and O gives ...
    Correct answer is 6 carbon atoms. As 180g contains 39.9% of carbon i.e. around 72g. on dividing by mo. wt of carbon i.e. 72÷6 we get the answer
    Explore Courses for IIT JAM exam
    Elemental analysis of an organic compound containing C, H and O gives percentage composition: C: 39.9 % and H: 6.7 %. If the molecular weight of the compound is 180, the number of carbon atoms present in the molecule is________.Correct answer is between '6,6'. Can you explain this answer?
    Question Description
    Elemental analysis of an organic compound containing C, H and O gives percentage composition: C: 39.9 % and H: 6.7 %. If the molecular weight of the compound is 180, the number of carbon atoms present in the molecule is________.Correct answer is between '6,6'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about Elemental analysis of an organic compound containing C, H and O gives percentage composition: C: 39.9 % and H: 6.7 %. If the molecular weight of the compound is 180, the number of carbon atoms present in the molecule is________.Correct answer is between '6,6'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Elemental analysis of an organic compound containing C, H and O gives percentage composition: C: 39.9 % and H: 6.7 %. If the molecular weight of the compound is 180, the number of carbon atoms present in the molecule is________.Correct answer is between '6,6'. Can you explain this answer?.
    Solutions for Elemental analysis of an organic compound containing C, H and O gives percentage composition: C: 39.9 % and H: 6.7 %. If the molecular weight of the compound is 180, the number of carbon atoms present in the molecule is________.Correct answer is between '6,6'. Can you explain this answer? in English & in Hindi are available as part of our courses for IIT JAM. Download more important topics, notes, lectures and mock test series for IIT JAM Exam by signing up for free.
    Here you can find the meaning of Elemental analysis of an organic compound containing C, H and O gives percentage composition: C: 39.9 % and H: 6.7 %. If the molecular weight of the compound is 180, the number of carbon atoms present in the molecule is________.Correct answer is between '6,6'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Elemental analysis of an organic compound containing C, H and O gives percentage composition: C: 39.9 % and H: 6.7 %. If the molecular weight of the compound is 180, the number of carbon atoms present in the molecule is________.Correct answer is between '6,6'. Can you explain this answer?, a detailed solution for Elemental analysis of an organic compound containing C, H and O gives percentage composition: C: 39.9 % and H: 6.7 %. If the molecular weight of the compound is 180, the number of carbon atoms present in the molecule is________.Correct answer is between '6,6'. Can you explain this answer? has been provided alongside types of Elemental analysis of an organic compound containing C, H and O gives percentage composition: C: 39.9 % and H: 6.7 %. If the molecular weight of the compound is 180, the number of carbon atoms present in the molecule is________.Correct answer is between '6,6'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Elemental analysis of an organic compound containing C, H and O gives percentage composition: C: 39.9 % and H: 6.7 %. If the molecular weight of the compound is 180, the number of carbon atoms present in the molecule is________.Correct answer is between '6,6'. Can you explain this answer? tests, examples and also practice IIT JAM tests.
    Explore Courses for IIT JAM exam
    Signup for Free!
    Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
    10M+ students study on EduRev