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A eukaryotic gene of 1000 base pairs containing several introns encodes a protein of 11 kDa. Assuming that the average molecular weight of one amino acid is 110 Da, the total length (in base pairs) of all the introns of the gene is __________.
Correct answer is '697'. Can you explain this answer?
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A eukaryotic gene of 1000 base pairs containing several introns encode...
To determine the total length of all the introns in a eukaryotic gene, we need to calculate the difference between the length of the gene and the length of the protein it encodes.
Given:
- Length of the gene: 1000 base pairs
- Molecular weight of the protein: 11 kDa (kiloDaltons)
- Average molecular weight of one amino acid: 110 Da (Daltons)
1. Calculate the length of the protein:
To determine the length of the protein, we need to convert kiloDaltons to Daltons. Since 1 kDa = 1000 Da, the protein has a molecular weight of 11,000 Da.
2. Calculate the number of amino acids in the protein:
To find the number of amino acids, we divide the molecular weight of the protein by the average molecular weight of one amino acid:
Number of amino acids = Molecular weight of the protein / Average molecular weight of one amino acid
Number of amino acids = 11,000 Da / 110 Da
Number of amino acids = 100
3. Calculate the total length of the exons:
The exons are the coding regions of the gene that are spliced together to form the mature messenger RNA (mRNA). Since the length of the gene is given as 1000 base pairs and the protein-coding region is composed of exons, the total length of the exons can be assumed to be 1000 base pairs.
4. Calculate the total length of the introns:
To find the total length of the introns, we subtract the length of the exons from the length of the gene:
Total length of introns = Length of the gene - Total length of exons
Total length of introns = 1000 base pairs - 1000 base pairs
Total length of introns = 0 base pairs
Therefore, the correct answer should be 0 base pairs.
Note: The given answer of 697 base pairs for the total length of all the introns seems incorrect based on the information provided. It is possible that there may be an error in the question or the answer key.
Given:
- Length of the gene: 1000 base pairs
- Molecular weight of the protein: 11 kDa (kiloDaltons)
- Average molecular weight of one amino acid: 110 Da (Daltons)
1. Calculate the length of the protein:
To determine the length of the protein, we need to convert kiloDaltons to Daltons. Since 1 kDa = 1000 Da, the protein has a molecular weight of 11,000 Da.
2. Calculate the number of amino acids in the protein:
To find the number of amino acids, we divide the molecular weight of the protein by the average molecular weight of one amino acid:
Number of amino acids = Molecular weight of the protein / Average molecular weight of one amino acid
Number of amino acids = 11,000 Da / 110 Da
Number of amino acids = 100
3. Calculate the total length of the exons:
The exons are the coding regions of the gene that are spliced together to form the mature messenger RNA (mRNA). Since the length of the gene is given as 1000 base pairs and the protein-coding region is composed of exons, the total length of the exons can be assumed to be 1000 base pairs.
4. Calculate the total length of the introns:
To find the total length of the introns, we subtract the length of the exons from the length of the gene:
Total length of introns = Length of the gene - Total length of exons
Total length of introns = 1000 base pairs - 1000 base pairs
Total length of introns = 0 base pairs
Therefore, the correct answer should be 0 base pairs.
Note: The given answer of 697 base pairs for the total length of all the introns seems incorrect based on the information provided. It is possible that there may be an error in the question or the answer key.
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Community Answer
A eukaryotic gene of 1000 base pairs containing several introns encode...
We are given 1000 bp encode a protein of 11kda
1 kda =1000da so we have 11000 da protein
we have 110 avg molecular weight of one amino acid
dividing the total weight of the protein that is 11000 daltons by the molecular weight of one amino acid that is 110 daltons we will get the number of amino acids in the protein now we know that that protein contains 100 amino acid
one amino acid is encoded by three base pairs or one codon 100 amino acids will be coded by 100 x 3 is equals to 300 base pairs now we know that 300 base pairs code for our 100 amino acids we need to remember here that we also have one stop codon in the mRNA so this makes a total of 303 base pairs that will be coding for our total protein mRNA now if we subtract 303 from 1000 we will get the total number of base pairs that will be coding for the introns
that is equal to 697
1 kda =1000da so we have 11000 da protein
we have 110 avg molecular weight of one amino acid
dividing the total weight of the protein that is 11000 daltons by the molecular weight of one amino acid that is 110 daltons we will get the number of amino acids in the protein now we know that that protein contains 100 amino acid
one amino acid is encoded by three base pairs or one codon 100 amino acids will be coded by 100 x 3 is equals to 300 base pairs now we know that 300 base pairs code for our 100 amino acids we need to remember here that we also have one stop codon in the mRNA so this makes a total of 303 base pairs that will be coding for our total protein mRNA now if we subtract 303 from 1000 we will get the total number of base pairs that will be coding for the introns
that is equal to 697
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A eukaryotic gene of 1000 base pairs containing several introns encodes a protein of 11 kDa. Assuming that the average molecular weight of one amino acid is 110 Da, the total length (in base pairs) of all the introns of the gene is __________.Correct answer is '697'. Can you explain this answer?
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A eukaryotic gene of 1000 base pairs containing several introns encodes a protein of 11 kDa. Assuming that the average molecular weight of one amino acid is 110 Da, the total length (in base pairs) of all the introns of the gene is __________.Correct answer is '697'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about A eukaryotic gene of 1000 base pairs containing several introns encodes a protein of 11 kDa. Assuming that the average molecular weight of one amino acid is 110 Da, the total length (in base pairs) of all the introns of the gene is __________.Correct answer is '697'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A eukaryotic gene of 1000 base pairs containing several introns encodes a protein of 11 kDa. Assuming that the average molecular weight of one amino acid is 110 Da, the total length (in base pairs) of all the introns of the gene is __________.Correct answer is '697'. Can you explain this answer?.
A eukaryotic gene of 1000 base pairs containing several introns encodes a protein of 11 kDa. Assuming that the average molecular weight of one amino acid is 110 Da, the total length (in base pairs) of all the introns of the gene is __________.Correct answer is '697'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about A eukaryotic gene of 1000 base pairs containing several introns encodes a protein of 11 kDa. Assuming that the average molecular weight of one amino acid is 110 Da, the total length (in base pairs) of all the introns of the gene is __________.Correct answer is '697'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A eukaryotic gene of 1000 base pairs containing several introns encodes a protein of 11 kDa. Assuming that the average molecular weight of one amino acid is 110 Da, the total length (in base pairs) of all the introns of the gene is __________.Correct answer is '697'. Can you explain this answer?.
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