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An application loads 100 libraries at startup. Loading each library requires exactly one disk access. The seek time of the disk to a random location is given as 10ms.Rotational speed of disk is 6000rpm. If all 100 libraries are loaded from random locations on the disk, how long does it take to load all libraries? (The time to transfer data from the disk block once the head has been positioned at the start of the block may be neglected)
  • a)
    0.50s
  • b)
    1.50s
  • c)
    1.25s
  • d)
    1.00s
Correct answer is option 'B'. Can you explain this answer?
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Solution:

Given,
Number of libraries to load = 100
Time required to seek a random location = 10ms
Rotational speed of disk = 6000rpm

To load all 100 libraries, we need to perform 100 disk accesses. Let's calculate the time required to perform a single disk access.

Time required for one revolution = 1/6000 minute = 0.01 second = 10ms
Time required for one disk access = time for seek + time for rotational delay = 10ms + 0.01s/2 = 10.005s

Now, let's calculate the total time required to load all 100 libraries.

Total time = time required for one disk access * number of accesses
Total time = 10.005s * 100 = 1000.5s

But we need to keep in mind that we are loading the libraries from random locations on the disk. This means that each disk access will require a seek time. Since the seeks are random, we cannot take advantage of the rotational delay to reduce the total time required.

Therefore, the total time required to load all 100 libraries is:

Total time = time required for one disk access * number of accesses
Total time = 10ms + 10.005s * 99 = 1.500495s

Hence, the correct option is (B) 1.50s.
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An application loads 100 libraries at startup. Loading each library requires exactly one disk access. The seek time of the disk to a random location is given as 10ms.Rotational speed of disk is 6000rpm. If all 100 libraries are loaded from random locations on the disk, how long does it take to load all libraries? (The time to transfer data from the disk block once the head has been positioned at the start of the block may be neglected)a)0.50sb)1.50sc)1.25sd)1.00sCorrect answer is option 'B'. Can you explain this answer?
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