Computer Science Engineering (CSE) Exam > Computer Science Engineering (CSE) Questions > Let P be a regular language and Q be a contex...
Start Learning for Free
Let P be a regular language and Q be a context free language such that Q ⊆ P. (For example, let P be the language represented by the regular expression p*q* and Q be {pnqn | n ∈ N}).
Q. Then which of the following is ALWAYS regular?
- a)P ∩ Q
- b)P − Q
- c)∑ * − P
- d)∑ * − Q
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
Let P be a regular language and Q be a context free language such that...
Σ* − P is the complement of P so it is always regular,
since regular languages are closed under complementation
Most Upvoted Answer
Let P be a regular language and Q be a context free language such that...
Explanation:
To determine which of the given options is always regular, we need to analyze the properties of regular and context-free languages.
- A regular language can be represented by a regular expression or can be accepted by a finite automaton.
- A context-free language can be generated by a context-free grammar or accepted by a pushdown automaton.
P Q:
If we concatenate a regular language P with a context-free language Q, the resulting language may or may not be regular. It depends on the specific languages P and Q.
P Q:
If we take the intersection of a regular language P and a context-free language Q, the resulting language is always regular. This is because the intersection of a regular language and a context-free language can be recognized by a finite automaton, which proves that the resulting language is regular.
* P:
If we take the Kleene star (closure) of a regular language P, the resulting language is always regular. This is because the Kleene star operation can be implemented using a finite automaton, which proves that the resulting language is regular.
* Q:
If we take the Kleene star (closure) of a context-free language Q, the resulting language may or may not be regular. It depends on the specific language Q. The Kleene star of a context-free language can be recognized by a pushdown automaton, but it may not be possible to convert this pushdown automaton into an equivalent finite automaton in some cases.
Therefore, based on the properties of regular and context-free languages, option C (* P) is the only one that is always regular.
To determine which of the given options is always regular, we need to analyze the properties of regular and context-free languages.
- A regular language can be represented by a regular expression or can be accepted by a finite automaton.
- A context-free language can be generated by a context-free grammar or accepted by a pushdown automaton.
P Q:
If we concatenate a regular language P with a context-free language Q, the resulting language may or may not be regular. It depends on the specific languages P and Q.
P Q:
If we take the intersection of a regular language P and a context-free language Q, the resulting language is always regular. This is because the intersection of a regular language and a context-free language can be recognized by a finite automaton, which proves that the resulting language is regular.
* P:
If we take the Kleene star (closure) of a regular language P, the resulting language is always regular. This is because the Kleene star operation can be implemented using a finite automaton, which proves that the resulting language is regular.
* Q:
If we take the Kleene star (closure) of a context-free language Q, the resulting language may or may not be regular. It depends on the specific language Q. The Kleene star of a context-free language can be recognized by a pushdown automaton, but it may not be possible to convert this pushdown automaton into an equivalent finite automaton in some cases.
Therefore, based on the properties of regular and context-free languages, option C (* P) is the only one that is always regular.
Attention Computer Science Engineering (CSE) Students!
To make sure you are not studying endlessly, EduRev has designed Computer Science Engineering (CSE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Computer Science Engineering (CSE).
|
Explore Courses for Computer Science Engineering (CSE) exam
|
|
Similar Computer Science Engineering (CSE) Doubts
Top Courses for Computer Science Engineering (CSE)View all
Let P be a regular language and Q be a context free language such that Q ⊆ P. (For example, let P be the language represented by the regular expression p*q* and Q be {pnqn | n ∈ N}).Q. Then which of the following is ALWAYS regular?a)P ∩ Qb)P − Qc)∑ * − Pd)∑ * − QCorrect answer is option 'C'. Can you explain this answer?
Question Description
Let P be a regular language and Q be a context free language such that Q ⊆ P. (For example, let P be the language represented by the regular expression p*q* and Q be {pnqn | n ∈ N}).Q. Then which of the following is ALWAYS regular?a)P ∩ Qb)P − Qc)∑ * − Pd)∑ * − QCorrect answer is option 'C'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Let P be a regular language and Q be a context free language such that Q ⊆ P. (For example, let P be the language represented by the regular expression p*q* and Q be {pnqn | n ∈ N}).Q. Then which of the following is ALWAYS regular?a)P ∩ Qb)P − Qc)∑ * − Pd)∑ * − QCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let P be a regular language and Q be a context free language such that Q ⊆ P. (For example, let P be the language represented by the regular expression p*q* and Q be {pnqn | n ∈ N}).Q. Then which of the following is ALWAYS regular?a)P ∩ Qb)P − Qc)∑ * − Pd)∑ * − QCorrect answer is option 'C'. Can you explain this answer?.
Let P be a regular language and Q be a context free language such that Q ⊆ P. (For example, let P be the language represented by the regular expression p*q* and Q be {pnqn | n ∈ N}).Q. Then which of the following is ALWAYS regular?a)P ∩ Qb)P − Qc)∑ * − Pd)∑ * − QCorrect answer is option 'C'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Let P be a regular language and Q be a context free language such that Q ⊆ P. (For example, let P be the language represented by the regular expression p*q* and Q be {pnqn | n ∈ N}).Q. Then which of the following is ALWAYS regular?a)P ∩ Qb)P − Qc)∑ * − Pd)∑ * − QCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let P be a regular language and Q be a context free language such that Q ⊆ P. (For example, let P be the language represented by the regular expression p*q* and Q be {pnqn | n ∈ N}).Q. Then which of the following is ALWAYS regular?a)P ∩ Qb)P − Qc)∑ * − Pd)∑ * − QCorrect answer is option 'C'. Can you explain this answer?.
Solutions for Let P be a regular language and Q be a context free language such that Q ⊆ P. (For example, let P be the language represented by the regular expression p*q* and Q be {pnqn | n ∈ N}).Q. Then which of the following is ALWAYS regular?a)P ∩ Qb)P − Qc)∑ * − Pd)∑ * − QCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Computer Science Engineering (CSE).
Download more important topics, notes, lectures and mock test series for Computer Science Engineering (CSE) Exam by signing up for free.
Here you can find the meaning of Let P be a regular language and Q be a context free language such that Q ⊆ P. (For example, let P be the language represented by the regular expression p*q* and Q be {pnqn | n ∈ N}).Q. Then which of the following is ALWAYS regular?a)P ∩ Qb)P − Qc)∑ * − Pd)∑ * − QCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Let P be a regular language and Q be a context free language such that Q ⊆ P. (For example, let P be the language represented by the regular expression p*q* and Q be {pnqn | n ∈ N}).Q. Then which of the following is ALWAYS regular?a)P ∩ Qb)P − Qc)∑ * − Pd)∑ * − QCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Let P be a regular language and Q be a context free language such that Q ⊆ P. (For example, let P be the language represented by the regular expression p*q* and Q be {pnqn | n ∈ N}).Q. Then which of the following is ALWAYS regular?a)P ∩ Qb)P − Qc)∑ * − Pd)∑ * − QCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Let P be a regular language and Q be a context free language such that Q ⊆ P. (For example, let P be the language represented by the regular expression p*q* and Q be {pnqn | n ∈ N}).Q. Then which of the following is ALWAYS regular?a)P ∩ Qb)P − Qc)∑ * − Pd)∑ * − QCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Let P be a regular language and Q be a context free language such that Q ⊆ P. (For example, let P be the language represented by the regular expression p*q* and Q be {pnqn | n ∈ N}).Q. Then which of the following is ALWAYS regular?a)P ∩ Qb)P − Qc)∑ * − Pd)∑ * − QCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Computer Science Engineering (CSE) tests.
|
|
Explore Courses for Computer Science Engineering (CSE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup