A can do a work in 6 days while B can do the same work in 8 days. With...
**Given information:**
- A can do the work in 6 days.
- B can do the work in 8 days.
- With the help of a boy, they completed the work in 3 days.
- They received Rs. 200 for completing the work.
- We need to find the share of the boy in the total money.
**Calculating the efficiency of A, B, and the boy:**
- Let's assume that the total work is 48 units (LCM of 6 and 8).
- A can complete 48 units of work in 6 days, which means his efficiency is 48/6 = 8 units per day.
- B can complete 48 units of work in 8 days, which means his efficiency is 48/8 = 6 units per day.
- Let's assume the efficiency of the boy is x units per day.
**Calculating the total work done:**
- A and B, along with the boy, completed the work in 3 days.
- So, the total work done is (8 + 6 + x) units per day * 3 days = 48 units.
**Calculating the share of each person:**
- A's share = (A's efficiency / Total efficiency) * Total money = (8/14) * 200 = Rs. 114.29
- B's share = (B's efficiency / Total efficiency) * Total money = (6/14) * 200 = Rs. 85.71
- Boy's share = (Boy's efficiency / Total efficiency) * Total money = (x/14) * 200
**Calculating the value of x:**
- A's share + B's share + Boy's share = Total money
- Rs. 114.29 + Rs. 85.71 + (x/14) * 200 = Rs. 200
- Rs. 200 + (x/14) * 200 = Rs. 200
- (x/14) * 200 = 0
- x = 0
**Conclusion:**
- The value of x is 0, which means the boy did not contribute to the work or the total money earned.
- Therefore, the share of the boy is Rs. 0.
Answer: The share of the boy is Rs. 0.
A can do a work in 6 days while B can do the same work in 8 days. With...
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