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Hydrogen and oxygen ombined in the ratio of 1:8 by mass to form water . what mass of oxygen gas would be required to react completely with 3g of hydrogen gas?
Most Upvoted Answer
Hydrogen and oxygen ombined in the ratio of 1:8 by mass to form water...
Explanation:

Concept: The Law of Conservation of Mass states that during a chemical reaction, the total mass of the reactants is equal to the total mass of the products.

Given: Hydrogen and Oxygen combine in the ratio of 1:8 by mass to form water.

To find: Mass of oxygen gas required to react completely with 3g of hydrogen gas.

Solution:

1. Finding the molecular formula of water:

The molecular formula of water is H2O.

2. Finding the molar mass of water:

The molar mass of water is 18g/mol.

3. Calculating the mass of oxygen required to react with 3g of hydrogen:

From the given ratio, the mass of oxygen required to react with 1g of hydrogen is 8g.

Therefore, the mass of oxygen required to react with 3g of hydrogen is:

8g x 3g = 24g

4. Converting the mass of oxygen to moles:

The molar mass of oxygen is 16g/mol.

Number of moles of oxygen required = Mass of oxygen required / Molar mass of oxygen

Number of moles of oxygen required = 24g / 16g/mol = 1.5 mol

Therefore, 1.5 mol of oxygen gas would be required to react completely with 3g of hydrogen gas.

Conclusion:

Hence, we have calculated that the mass of oxygen required to react completely with 3g of hydrogen gas is 24g and the number of moles of oxygen required is 1.5 mol.
Community Answer
Hydrogen and oxygen ombined in the ratio of 1:8 by mass to form water...
Hydrogen = 1g. Oxygen = 8g
Hydrogen = 3g. Oxygen = 8×3g = 24g.
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Hydrogen and oxygen ombined in the ratio of 1:8 by mass to form water . what mass of oxygen gas would be required to react completely with 3g of hydrogen gas?
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