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Consider a frame 1101011011 and a generator polynomial 10011. What is the number of 1’s in the transmitted frame?
________
    Correct answer is '10'. Can you explain this answer?
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    Consider a frame 1101011011 and a generator polynomial 10011. What is ...
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    Consider a frame 1101011011 and a generator polynomial 10011. What is ...
    Explanation:

    Step 1: Append zeros to the frame

    Frame: 1101011011
    Generator polynomial: 10011

    Append 4 zeros to the frame:
    11010110110000

    Step 2: Divide the frame by the generator polynomial

    Divide 11010110110000 by 10011 using binary long division:

    ```
    1011010010100
    10011) 11010110110000
    10011
    ------
    10110
    10011
    -----
    11010
    10011
    -----
    1011
    1001
    ----
    1100
    1001
    ----
    1010
    1001
    ----
    1100
    1001
    ----
    1010
    1001
    ----
    1100
    1001
    ----
    1011
    1001
    ----
    1100
    1001
    ----
    1010
    ```

    Step 3: Calculate the remainder

    The remainder is 1010.

    Step 4: Append the remainder to the original frame to get the transmitted frame

    The transmitted frame is 11010110111010.

    Step 5: Count the number of 1s in the transmitted frame

    The number of 1s in the transmitted frame is 10.

    Conclusion: Therefore, the correct answer is 10.
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    Consider a frame 1101011011 and a generator polynomial 10011. What is the number of 1’s in the transmitted frame?________Correct answer is '10'. Can you explain this answer?
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