Computer Science Engineering (CSE) Exam > Computer Science Engineering (CSE) Questions > Consider a frame 1101011011 and a generator p...
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Consider a frame 1101011011 and a generator polynomial 10011. What is the number of 1’s in the transmitted frame?
________
________
Correct answer is '10'. Can you explain this answer?
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Consider a frame 1101011011 and a generator polynomial 10011. What is ...
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Consider a frame 1101011011 and a generator polynomial 10011. What is ...
Explanation:
Step 1: Append zeros to the frame
Frame: 1101011011
Generator polynomial: 10011
Append 4 zeros to the frame:
11010110110000
Step 2: Divide the frame by the generator polynomial
Divide 11010110110000 by 10011 using binary long division:
```
1011010010100
10011) 11010110110000
10011
------
10110
10011
-----
11010
10011
-----
1011
1001
----
1100
1001
----
1010
1001
----
1100
1001
----
1010
1001
----
1100
1001
----
1011
1001
----
1100
1001
----
1010
```
Step 3: Calculate the remainder
The remainder is 1010.
Step 4: Append the remainder to the original frame to get the transmitted frame
The transmitted frame is 11010110111010.
Step 5: Count the number of 1s in the transmitted frame
The number of 1s in the transmitted frame is 10.
Conclusion: Therefore, the correct answer is 10.
Step 1: Append zeros to the frame
Frame: 1101011011
Generator polynomial: 10011
Append 4 zeros to the frame:
11010110110000
Step 2: Divide the frame by the generator polynomial
Divide 11010110110000 by 10011 using binary long division:
```
1011010010100
10011) 11010110110000
10011
------
10110
10011
-----
11010
10011
-----
1011
1001
----
1100
1001
----
1010
1001
----
1100
1001
----
1010
1001
----
1100
1001
----
1011
1001
----
1100
1001
----
1010
```
Step 3: Calculate the remainder
The remainder is 1010.
Step 4: Append the remainder to the original frame to get the transmitted frame
The transmitted frame is 11010110111010.
Step 5: Count the number of 1s in the transmitted frame
The number of 1s in the transmitted frame is 10.
Conclusion: Therefore, the correct answer is 10.
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Consider a frame 1101011011 and a generator polynomial 10011. What is the number of 1’s in the transmitted frame?________Correct answer is '10'. Can you explain this answer?
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