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Assume CSMA/CD protocol. Find the least frame length in bytes for a 2 Mbps bit rate and 1.5km long network where propagation delay is 4.25 nano seconds per metre.
Correct answer is '3.1875'. Can you explain this answer?
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Assume CSMA/CD protocol. Find the least frame length in bytes for a 2 ...
Minimum frame size for CSMA/CD = 2 X Propagation delay
Minimum frame size = 2 X Propagation Delay per metre X Length of the network X Bit Rate
Minimum frame size = 2 X 4.25 X 10– 9 X 1.5 X 103 X 2 X 106
So, minimum frame size = 25.50/8 = 3.1875 bytes
Minimum frame size = 2 X Propagation Delay per metre X Length of the network X Bit Rate
Minimum frame size = 2 X 4.25 X 10– 9 X 1.5 X 103 X 2 X 106
So, minimum frame size = 25.50/8 = 3.1875 bytes
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Assume CSMA/CD protocol. Find the least frame length in bytes for a 2 ...
CSMA/CD Protocol and Frame Length Calculation
CSMA/CD Protocol:
CSMA/CD stands for Carrier Sense Multiple Access with Collision Detection. It is a protocol used in Ethernet networks to avoid collisions between data packets sent simultaneously by two or more devices on the same network segment.
Frame Length Calculation:
The frame length is the length of the data packet transmitted over the network. It is calculated by adding the length of the data to the length of the header and trailer.
Given Information:
Bit rate = 2 Mbps
Network length = 1.5 km
Propagation delay = 4.25 ns/m
Calculation:
Propagation delay = Distance / Propagation speed
Propagation speed = 2*10^8 m/s
Propagation delay = 4.25 ns/m * 1.5*10^3 m = 6.375 µs
The minimum frame length can be calculated as follows:
Frame length = 2 * Propagation delay * Bit rate
Frame length = 2 * 6.375 µs * 2 Mbps
Frame length = 25.5 bits
The minimum frame length in bytes can be calculated as follows:
Frame length (bytes) = Frame length / 8
Frame length (bytes) = 25.5 bits / 8
Frame length (bytes) = 3.1875 bytes
Answer:
The least frame length in bytes for a 2 Mbps bit rate and 1.5km long network where propagation delay is 4.25 nano seconds per metre is 3.1875 bytes.
CSMA/CD Protocol:
CSMA/CD stands for Carrier Sense Multiple Access with Collision Detection. It is a protocol used in Ethernet networks to avoid collisions between data packets sent simultaneously by two or more devices on the same network segment.
Frame Length Calculation:
The frame length is the length of the data packet transmitted over the network. It is calculated by adding the length of the data to the length of the header and trailer.
Given Information:
Bit rate = 2 Mbps
Network length = 1.5 km
Propagation delay = 4.25 ns/m
Calculation:
Propagation delay = Distance / Propagation speed
Propagation speed = 2*10^8 m/s
Propagation delay = 4.25 ns/m * 1.5*10^3 m = 6.375 µs
The minimum frame length can be calculated as follows:
Frame length = 2 * Propagation delay * Bit rate
Frame length = 2 * 6.375 µs * 2 Mbps
Frame length = 25.5 bits
The minimum frame length in bytes can be calculated as follows:
Frame length (bytes) = Frame length / 8
Frame length (bytes) = 25.5 bits / 8
Frame length (bytes) = 3.1875 bytes
Answer:
The least frame length in bytes for a 2 Mbps bit rate and 1.5km long network where propagation delay is 4.25 nano seconds per metre is 3.1875 bytes.
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Assume CSMA/CD protocol. Find the least frame length in bytes for a 2 Mbps bit rate and 1.5km long network where propagation delay is 4.25 nano seconds per metre.Correct answer is '3.1875'. Can you explain this answer?
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