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The numbers 3446, 5887 and 2445 are put side by side in the same order making a 100 digits number. Find the remainder when this 100 digit number is divided by 9.
  • a)
    1
  • b)
    4
  • c)
    3
  • d)
    2
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The numbers 3446, 5887 and 2445 are put side by side in the same order...
Since the number is of 100 digits and 3446, 5887 and 2445 are put side by side in the same order;
∴ 3446 must be repeated 9 times, 5887 & 2445 must be repeated 8 times;
∴ Sum of digits of 100 digits number = [3 + 4 + 4 + 6] × 9 + [5 + 8 + 8 + 7 + 2 + 4 + 4 + 5] × 8
⇒ 153 + 344
⇒ 497
Reminder when 497 is divided by 9 = 2
Hence, the remainder when the 100 digit number is divided by 9 would be 2.
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The numbers 3446, 5887 and 2445 are put side by side in the same order making a 100 digits number. Find the remainder when this 100 digit number is divided by 9.a)1b)4c)3d)2Correct answer is option 'D'. Can you explain this answer?
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