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A stone is dropped from the top of a tower 500 m high into a pond of water at the base of the tower. When is the splash heard at the top? Given, g= 10 m s^-2 and speed of sound= 340 m s^-1.?
Most Upvoted Answer
A stone is dropped from the top of a tower 500 m high into a pond of w...
Calculating the time taken for the stone to reach the water


  • Given, height of the tower (h) = 500 m, acceleration due to gravity (g) = 10 m/s^2

  • Using the formula, h = (1/2)gt^2, we can calculate the time taken (t) for the stone to reach the water

  • Plugging in the values, we get t = sqrt(2h/g) = sqrt(2*500/10) = 10 sqrt(10) seconds



Calculating the distance travelled by sound in the same time


  • Speed of sound (v) = 340 m/s

  • Using the formula, distance = speed x time, we can calculate the distance travelled by sound in the same time taken by the stone to reach the water

  • Plugging in the values, we get distance = 340 x 10 sqrt(10) = 3400 sqrt(10) meters



Calculating the time taken for the sound to reach the top of the tower


  • Using the formula, distance = speed x time, we can calculate the time taken (t') for the sound to reach the top of the tower

  • Plugging in the values, we get 3400 sqrt(10) = 340 x t'

  • Therefore, t' = sqrt(10) seconds



Adding the time taken for the stone and sound


  • The time taken for the stone to reach the water (t) and for the sound to travel to the top of the tower (t') are different

  • Therefore, we need to add the two times to get the total time taken for the splash to be heard at the top of the tower

  • Plugging in the values, we get the total time taken = t + t' = 10 sqrt(10) + sqrt(10) = 11 sqrt(10) seconds



Conclusion

Therefore, the splash is heard at the top of the tower after 11 sqrt(10) seconds.
Community Answer
A stone is dropped from the top of a tower 500 m high into a pond of w...
Height=displacement=500m(s)
Initial velocity(u)=0(due to downward movement)
Acceleration due to gravity=10ms2
Speed of sound =340 ms1
From the second equation of motion,
s=ut+1/2at2
500=0×t+1/2×10*×2
500=0+5t2
500=5t2
t2=500/5
t2=100
t=10 seconds
Now the time for echo of the sound back to the tower would be 500/340 speed of the sound =25/17=1.47
Total =10+1.47
=11.47 seconds
thus, total time for hearing the sound flashing back to the tower is 11.47seconds.
Hope it will help.
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A stone is dropped from the top of a tower 500 m high into a pond of water at the base of the tower. When is the splash heard at the top? Given, g= 10 m s^-2 and speed of sound= 340 m s^-1.?
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A stone is dropped from the top of a tower 500 m high into a pond of water at the base of the tower. When is the splash heard at the top? Given, g= 10 m s^-2 and speed of sound= 340 m s^-1.? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A stone is dropped from the top of a tower 500 m high into a pond of water at the base of the tower. When is the splash heard at the top? Given, g= 10 m s^-2 and speed of sound= 340 m s^-1.? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A stone is dropped from the top of a tower 500 m high into a pond of water at the base of the tower. When is the splash heard at the top? Given, g= 10 m s^-2 and speed of sound= 340 m s^-1.?.
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