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A stone is dropped into a well in which the level of water is h, below the top of the well. If v is velocity of sound, then time T after which the splash is heard is equal to
  • a)
  • b)
  • c)
  • d)
Correct answer is 'C'. Can you explain this answer?
Verified Answer
A stone is dropped into a well in which the level of water is h, below...
Here T is the time taken by the stone to reach to the water level plus time taken by the sound to come out from the water level to top of the well. 

Now, if T1 is the time taken by the stone to reach the water level then,
h = 1/2 x g x T1^2
=> T1 = (2h/g)^1/2

Now since v is the velocity of the sound, time taken by velocity to reach the top is
T2 = h/v

So, total time is T = T1 + T2 = (2h/g)^1/2 + h/v

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Most Upvoted Answer
A stone is dropped into a well in which the level of water is h, below...
Time taken for the ball to reach the bottom 

= (2h/g)^1/2

Time taken by sound to reach the top 
= h/v 

Thus total time= (2h/g)^1/2 + h/v

Thus answer is B
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