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a coin us drooped into a deep well and is heard to hit the water 3.41s after being dropped. determine the depth of the well (ans 57m)
Most Upvoted Answer
a coin us drooped into a deep well and is heard to hit the water 3.41s...
Problem: A coin is dropped into a deep well and is heard to hit the water 3.41s after being dropped. Determine the depth of the well.

Solution:
To determine the depth of the well, we need to use the equation of motion for a freely falling object. The equation is:

h = 1/2 gt^2

where h is the height or depth of the well, g is the acceleration due to gravity (9.8 m/s^2), and t is the time it takes for the coin to hit the water.

Step 1: Identify the given values

t = 3.41s (the time it takes for the coin to hit the water)
g = 9.8 m/s^2 (acceleration due to gravity)

Step 2: Substitute the values into the equation

h = 1/2 gt^2
h = 1/2 * 9.8 m/s^2 * (3.41s)^2
h = 1/2 * 9.8 m/s^2 * 11.6281s^2
h = 56.9054m

Step 3: Round off the answer to the appropriate number of significant figures

The answer is 57m.

Conclusion: The depth of the well is 57 meters.
Community Answer
a coin us drooped into a deep well and is heard to hit the water 3.41s...
t=3.41su=0 m/sg=9.8 m/s²h=ut+½gt² =0+½×9.8×3.41² =56.9 m ≈57 m
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a coin us drooped into a deep well and is heard to hit the water 3.41s after being dropped. determine the depth of the well (ans 57m)
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