Class 12 Exam > Class 12 Questions > An organic compound X is oxidised by using ac...
Start Learning for Free
An organic compound X is oxidised by using acidified K2Cr2O7. The product obtained reacts with Phenyl hydrazine but does not answer silver mirror test. The possible structure of X is
- a)CH3CH2OH
- b)CH3CHO
- c)(CH3)2CHOH
- d)None of the these
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
An organic compound X is oxidised by using acidifiedK2Cr2O7. The produ...
Yup...it will be propan-2-ol..by oxidation it..it will convert into acetone and it reacts with phenyl hydrazine,it produces acetone phenyl hydrazone and there is no aldehyde grp in acetone. so it doesn't react in silver mirror test means with tollen's reagent..
Free Test
FREE
| Start Free Test |
Community Answer
An organic compound X is oxidised by using acidifiedK2Cr2O7. The produ...
Answer:
Explanation:
To determine the possible structure of compound X, we need to consider the given information about its reactions with acidified K2Cr2O7 and phenyl hydrazine, as well as its non-reactivity in the silver mirror test.
Reaction with Acidified K2Cr2O7:
The oxidation of an organic compound by acidified K2Cr2O7 involves the conversion of the Cr(VI) in K2Cr2O7 to Cr(III). In this process, the organic compound is oxidized while K2Cr2O7 is reduced.
Phenyl Hydrazine Test:
Phenyl hydrazine is commonly used to test for the presence of carbonyl compounds, particularly aldehydes and ketones. It reacts with carbonyl compounds to form hydrazones, which are yellow or orange precipitates.
Silver Mirror Test:
The silver mirror test is used to identify the presence of an aldehyde functional group in an organic compound. It involves the reaction of the compound with Tollens' reagent (ammoniacal silver nitrate), which results in the formation of a silver mirror on the walls of the test tube.
Possible Structures:
Let's consider the given options one by one:
a) CH3CH2OH (Ethanol)
- Ethanol can be oxidized by acidified K2Cr2O7 to form ethanal (CH3CHO).
- Ethanal can react with phenyl hydrazine to form a yellow/orange precipitate.
- Ethanol can also produce a silver mirror when subjected to the silver mirror test.
- Therefore, option a) is not the correct answer.
b) CH3CHO (Ethanal)
- Ethanal can be oxidized by acidified K2Cr2O7 to form ethanoic acid (CH3COOH).
- Ethanal can react with phenyl hydrazine to form a yellow/orange precipitate.
- Ethanal can also produce a silver mirror when subjected to the silver mirror test.
- Therefore, option b) is not the correct answer.
c) (CH3)2CHOH (Isopropyl alcohol)
- Isopropyl alcohol can be oxidized by acidified K2Cr2O7 to form acetone ((CH3)2CO).
- Acetone does not react with phenyl hydrazine and does not form a yellow/orange precipitate.
- Acetone also does not produce a silver mirror when subjected to the silver mirror test.
- Therefore, option c) is the correct answer.
d) None of these
- The correct answer has already been determined to be option c) (CH3)2CHOH.
In conclusion, the possible structure of compound X is (CH3)2CHOH, which is isopropyl alcohol.
Explanation:
To determine the possible structure of compound X, we need to consider the given information about its reactions with acidified K2Cr2O7 and phenyl hydrazine, as well as its non-reactivity in the silver mirror test.
Reaction with Acidified K2Cr2O7:
The oxidation of an organic compound by acidified K2Cr2O7 involves the conversion of the Cr(VI) in K2Cr2O7 to Cr(III). In this process, the organic compound is oxidized while K2Cr2O7 is reduced.
Phenyl Hydrazine Test:
Phenyl hydrazine is commonly used to test for the presence of carbonyl compounds, particularly aldehydes and ketones. It reacts with carbonyl compounds to form hydrazones, which are yellow or orange precipitates.
Silver Mirror Test:
The silver mirror test is used to identify the presence of an aldehyde functional group in an organic compound. It involves the reaction of the compound with Tollens' reagent (ammoniacal silver nitrate), which results in the formation of a silver mirror on the walls of the test tube.
Possible Structures:
Let's consider the given options one by one:
a) CH3CH2OH (Ethanol)
- Ethanol can be oxidized by acidified K2Cr2O7 to form ethanal (CH3CHO).
- Ethanal can react with phenyl hydrazine to form a yellow/orange precipitate.
- Ethanol can also produce a silver mirror when subjected to the silver mirror test.
- Therefore, option a) is not the correct answer.
b) CH3CHO (Ethanal)
- Ethanal can be oxidized by acidified K2Cr2O7 to form ethanoic acid (CH3COOH).
- Ethanal can react with phenyl hydrazine to form a yellow/orange precipitate.
- Ethanal can also produce a silver mirror when subjected to the silver mirror test.
- Therefore, option b) is not the correct answer.
c) (CH3)2CHOH (Isopropyl alcohol)
- Isopropyl alcohol can be oxidized by acidified K2Cr2O7 to form acetone ((CH3)2CO).
- Acetone does not react with phenyl hydrazine and does not form a yellow/orange precipitate.
- Acetone also does not produce a silver mirror when subjected to the silver mirror test.
- Therefore, option c) is the correct answer.
d) None of these
- The correct answer has already been determined to be option c) (CH3)2CHOH.
In conclusion, the possible structure of compound X is (CH3)2CHOH, which is isopropyl alcohol.
|
Explore Courses for Class 12 exam
|
|
Similar Class 12 Doubts
An organic compound X is oxidised by using acidifiedK2Cr2O7. The product obtained reacts with Phenyl hydrazine but does not answer silver mirror test. The possible structure of X isa)CH3CH2OHb)CH3CHOc)(CH3)2CHOHd)None of the theseCorrect answer is option 'C'. Can you explain this answer?
Question Description
An organic compound X is oxidised by using acidifiedK2Cr2O7. The product obtained reacts with Phenyl hydrazine but does not answer silver mirror test. The possible structure of X isa)CH3CH2OHb)CH3CHOc)(CH3)2CHOHd)None of the theseCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about An organic compound X is oxidised by using acidifiedK2Cr2O7. The product obtained reacts with Phenyl hydrazine but does not answer silver mirror test. The possible structure of X isa)CH3CH2OHb)CH3CHOc)(CH3)2CHOHd)None of the theseCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organic compound X is oxidised by using acidifiedK2Cr2O7. The product obtained reacts with Phenyl hydrazine but does not answer silver mirror test. The possible structure of X isa)CH3CH2OHb)CH3CHOc)(CH3)2CHOHd)None of the theseCorrect answer is option 'C'. Can you explain this answer?.
An organic compound X is oxidised by using acidifiedK2Cr2O7. The product obtained reacts with Phenyl hydrazine but does not answer silver mirror test. The possible structure of X isa)CH3CH2OHb)CH3CHOc)(CH3)2CHOHd)None of the theseCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about An organic compound X is oxidised by using acidifiedK2Cr2O7. The product obtained reacts with Phenyl hydrazine but does not answer silver mirror test. The possible structure of X isa)CH3CH2OHb)CH3CHOc)(CH3)2CHOHd)None of the theseCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organic compound X is oxidised by using acidifiedK2Cr2O7. The product obtained reacts with Phenyl hydrazine but does not answer silver mirror test. The possible structure of X isa)CH3CH2OHb)CH3CHOc)(CH3)2CHOHd)None of the theseCorrect answer is option 'C'. Can you explain this answer?.
Solutions for An organic compound X is oxidised by using acidifiedK2Cr2O7. The product obtained reacts with Phenyl hydrazine but does not answer silver mirror test. The possible structure of X isa)CH3CH2OHb)CH3CHOc)(CH3)2CHOHd)None of the theseCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of An organic compound X is oxidised by using acidifiedK2Cr2O7. The product obtained reacts with Phenyl hydrazine but does not answer silver mirror test. The possible structure of X isa)CH3CH2OHb)CH3CHOc)(CH3)2CHOHd)None of the theseCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
An organic compound X is oxidised by using acidifiedK2Cr2O7. The product obtained reacts with Phenyl hydrazine but does not answer silver mirror test. The possible structure of X isa)CH3CH2OHb)CH3CHOc)(CH3)2CHOHd)None of the theseCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for An organic compound X is oxidised by using acidifiedK2Cr2O7. The product obtained reacts with Phenyl hydrazine but does not answer silver mirror test. The possible structure of X isa)CH3CH2OHb)CH3CHOc)(CH3)2CHOHd)None of the theseCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of An organic compound X is oxidised by using acidifiedK2Cr2O7. The product obtained reacts with Phenyl hydrazine but does not answer silver mirror test. The possible structure of X isa)CH3CH2OHb)CH3CHOc)(CH3)2CHOHd)None of the theseCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice An organic compound X is oxidised by using acidifiedK2Cr2O7. The product obtained reacts with Phenyl hydrazine but does not answer silver mirror test. The possible structure of X isa)CH3CH2OHb)CH3CHOc)(CH3)2CHOHd)None of the theseCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 12 tests.
|
|
Explore Courses for Class 12 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup