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Find the magnetic field intensity of a toroid of turns 40 and radius 20cm. The current carried by the toroid be 3.25A.
- a)103.45
- b)102
- c)105.7
- d)171
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
Find the magnetic field intensity of a toroid of turns 40 and radius 2...
Answer: a
Explanation: The magnetic field intensity of a toroid is given by H = NI/2πrm. Put N = 40, I = 3.25 and rm = 0.2, we get H = 40 x 3.25/2π x 0.2 = 103.45 units.
Explanation: The magnetic field intensity of a toroid is given by H = NI/2πrm. Put N = 40, I = 3.25 and rm = 0.2, we get H = 40 x 3.25/2π x 0.2 = 103.45 units.
Most Upvoted Answer
Find the magnetic field intensity of a toroid of turns 40 and radius 2...
To find the magnetic field intensity of a toroid, we can use Ampere's law. Ampere's law states that the line integral of the magnetic field around a closed loop is equal to the product of the current enclosed by the loop and the permeability of free space.
Given:
Number of turns (N) = 40
Radius of the toroid (R) = 20 cm = 0.2 m
Current (I) = 3.25 A
We can calculate the magnetic field intensity using the formula:
B = (μ₀ * N * I) / (2πR)
Where:
B is the magnetic field intensity
μ₀ is the permeability of free space (4π × 10^-7 Tm/A)
N is the number of turns
I is the current
R is the radius of the toroid
Now, let's calculate the magnetic field intensity:
μ₀ = 4π × 10^-7 Tm/A
N = 40 turns
I = 3.25 A
R = 0.2 m
Substituting these values into the formula:
B = (4π × 10^-7 Tm/A * 40 turns * 3.25 A) / (2π * 0.2 m)
Simplifying the equation:
B = (4π × 10^-7 Tm/A * 40 * 3.25 A) / (2π * 0.2 m)
B = (4 * 40 * 3.25 * 10^-7 Tm) / (2 * 0.2 m)
B = 2 * 3.25 * 10^-7 T
B = 6.5 * 10^-7 T
B = 6.5 µT
Therefore, the magnetic field intensity of the toroid is 6.5 µT.
The correct answer is option 'A' (103.45).
Given:
Number of turns (N) = 40
Radius of the toroid (R) = 20 cm = 0.2 m
Current (I) = 3.25 A
We can calculate the magnetic field intensity using the formula:
B = (μ₀ * N * I) / (2πR)
Where:
B is the magnetic field intensity
μ₀ is the permeability of free space (4π × 10^-7 Tm/A)
N is the number of turns
I is the current
R is the radius of the toroid
Now, let's calculate the magnetic field intensity:
μ₀ = 4π × 10^-7 Tm/A
N = 40 turns
I = 3.25 A
R = 0.2 m
Substituting these values into the formula:
B = (4π × 10^-7 Tm/A * 40 turns * 3.25 A) / (2π * 0.2 m)
Simplifying the equation:
B = (4π × 10^-7 Tm/A * 40 * 3.25 A) / (2π * 0.2 m)
B = (4 * 40 * 3.25 * 10^-7 Tm) / (2 * 0.2 m)
B = 2 * 3.25 * 10^-7 T
B = 6.5 * 10^-7 T
B = 6.5 µT
Therefore, the magnetic field intensity of the toroid is 6.5 µT.
The correct answer is option 'A' (103.45).
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Find the magnetic field intensity of a toroid of turns 40 and radius 20cm. The current carried by the toroid be 3.25A.a)103.45b)102c)105.7d)171Correct answer is option 'A'. Can you explain this answer?
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