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For a particle with projection r = 2i – 3j + k and momentum p = i + 2j – 2k in meter and Kg m/sec respectively, calculate the magnitude of angular momentum:
- a)9.48 Kgm2sec-1
- b)11.89 Kgm2sec-1
- c)3.74 Kgm2sec-1
- d)None of these.
Correct answer is option 'A'. Can you explain this answer?
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For a particle with projection r = 2i – 3j + k and momentum p = ...
The projection of a particle, r, can be represented as a vector in three-dimensional space. In this case, the projection r is given as 2i, where i is the unit vector in the x-direction.
To represent this vector in three-dimensional space, we can use the Cartesian coordinate system. The Cartesian coordinate system consists of three axes - x, y, and z - which are mutually perpendicular to each other.
Since the projection r is given only in the x-direction, it means that the particle's position lies on the x-axis. The magnitude of the projection r is 2, indicating that the particle is located at a distance of 2 units along the positive x-axis.
Thus, the position of the particle is (2, 0, 0) in three-dimensional space.
To represent this vector in three-dimensional space, we can use the Cartesian coordinate system. The Cartesian coordinate system consists of three axes - x, y, and z - which are mutually perpendicular to each other.
Since the projection r is given only in the x-direction, it means that the particle's position lies on the x-axis. The magnitude of the projection r is 2, indicating that the particle is located at a distance of 2 units along the positive x-axis.
Thus, the position of the particle is (2, 0, 0) in three-dimensional space.
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