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An amplifier has an open-loop gain of 100, an input impedance of 10 kΩ and an output impedance of 200 Ω. A feedback factor of 0.99 is connected to the amplifier in a voltage series feedback configuration. The new input and output impedances respectively are
- a)100 K, 1Ω
- b)1 MΩ, 1 Ω
- c)1 MΩ, 2 Ω
- d)100 K,2Ω
Correct answer is option 'C'. Can you explain this answer?
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An amplifier has an open-loop gain of 100, an input impedance of 10 k&...
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An amplifier has an open-loop gain of 100, an input impedance of 10 k&...
Open-loop gain:
The open-loop gain of the amplifier is given as 100. This means that without any feedback, the amplifier can amplify the input signal by a factor of 100.
Input and output impedance:
The input impedance of the amplifier is given as 10 kΩ (kiloohms), and the output impedance is given as 200 Ω (ohms). The input impedance represents the load that the amplifier presents to the signal source, while the output impedance represents the source impedance that the amplifier presents to the load.
Voltage series feedback:
In this configuration, the feedback is connected in series with the output of the amplifier. The feedback factor, β, is given as 0.99. The feedback factor represents the fraction of the output signal that is fed back to the input.
Calculating the new input impedance:
The new input impedance, Zin, can be calculated using the formula:
Zin = (Zin0)/(1 + βA)
Where Zin0 is the original input impedance of the amplifier and A is the open-loop gain.
Substituting the given values, we get:
Zin = (10 kΩ)/(1 + 0.99 * 100)
Zin = (10 kΩ)/(1 + 99)
Zin = (10 kΩ)/(100)
Zin = 100 Ω
Therefore, the new input impedance is 100 Ω.
Calculating the new output impedance:
The new output impedance, Zout, can be calculated using the formula:
Zout = Zout0/(1 + βA)
Where Zout0 is the original output impedance of the amplifier.
Substituting the given values, we get:
Zout = 200Ω/(1 + 0.99 * 100)
Zout = 200Ω/(1 + 99)
Zout = 200Ω/(100)
Zout = 2 Ω
Therefore, the new output impedance is 2 Ω.
Conclusion:
The new input impedance is 100 Ω and the new output impedance is 2 Ω. Therefore, the correct answer is option 'C' - 1 MΩ, 2 Ω.
The open-loop gain of the amplifier is given as 100. This means that without any feedback, the amplifier can amplify the input signal by a factor of 100.
Input and output impedance:
The input impedance of the amplifier is given as 10 kΩ (kiloohms), and the output impedance is given as 200 Ω (ohms). The input impedance represents the load that the amplifier presents to the signal source, while the output impedance represents the source impedance that the amplifier presents to the load.
Voltage series feedback:
In this configuration, the feedback is connected in series with the output of the amplifier. The feedback factor, β, is given as 0.99. The feedback factor represents the fraction of the output signal that is fed back to the input.
Calculating the new input impedance:
The new input impedance, Zin, can be calculated using the formula:
Zin = (Zin0)/(1 + βA)
Where Zin0 is the original input impedance of the amplifier and A is the open-loop gain.
Substituting the given values, we get:
Zin = (10 kΩ)/(1 + 0.99 * 100)
Zin = (10 kΩ)/(1 + 99)
Zin = (10 kΩ)/(100)
Zin = 100 Ω
Therefore, the new input impedance is 100 Ω.
Calculating the new output impedance:
The new output impedance, Zout, can be calculated using the formula:
Zout = Zout0/(1 + βA)
Where Zout0 is the original output impedance of the amplifier.
Substituting the given values, we get:
Zout = 200Ω/(1 + 0.99 * 100)
Zout = 200Ω/(1 + 99)
Zout = 200Ω/(100)
Zout = 2 Ω
Therefore, the new output impedance is 2 Ω.
Conclusion:
The new input impedance is 100 Ω and the new output impedance is 2 Ω. Therefore, the correct answer is option 'C' - 1 MΩ, 2 Ω.
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An amplifier has an open-loop gain of 100, an input impedance of 10 kΩand an output impedance of 200 Ω. A feedback factor of 0.99 is connected to the amplifier in a voltage series feedback configuration. The new input and output impedances respectively area)100 K, 1Ω b)1 MΩ, 1Ωc)1 MΩ, 2 Ω d)100 K,2ΩCorrect answer is option 'C'. Can you explain this answer?
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